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Darina [25.2K]
3 years ago
8

Metals allow electrons to flow through and complete the circuit. Therefore they are called?

Physics
1 answer:
pickupchik [31]3 years ago
8 0

Answer:

the answer would be conductors

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2. Before 0.5-kg ball is dropped from a third story window 20 m above the sidewalk. What is the potential
Flauer [41]

Answer:

C

Explanation:

C

20*9.8*0.5

98

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3 years ago
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Light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance li
diamong [38]

So to solve this problem, we must convert units and then cancel units simultaneously:

(\frac{982,080,000ft}{s})*(\frac{32,000,000s}{1})*(\frac{12inches}{1ft})=3.77x10^{17} inches

Therefore we know that the distance that light travels in one year is 3.77x10^{17} inches.

7 0
4 years ago
How far apart are the fringes in the center of the pattern on a screen 4.3 m away? Express your answer to two significant figure
attashe74 [19]

Answer:

d = \frac{nLembda}{sin(theta)}

Explanation:

This comes from diffrection pattern equation used to locate fringe pattern, i will explain every variable in it here.

n = order of fringe = 0 1 2 3 .. and negative integars as well.

d is sacing between slits.

Theta = angle at which light-Ray is directed towards fringe.

It appears that the distance between consectice fringes would same as the distance between two slits 'd'.

therefore calculating that distance should give us the distance between two fringe patters.

Note we don't use transversal seperation distance here.

4 0
3 years ago
- How long does it take a packet of length 1,000 bytes to propagate over a link of distance 2,500 km, propagation speed 2.5 *10^
Sunny_sXe [5.5K]

Answer:

It will take 0.01 s or 10 ms

Solution:

As per the question:

Length of the packet, L = 1,000 bytes = 1000\times 8 = 8000 bits

Distance, d = 2500 km = 2.5\times 10^{6}\ m

Speed of propagation, s = 2.5\times 10^{8}\ m/s

Transmission rate, R = 2 Mbps

Now,

Propagation time, t can be calculated as:

t = \frac{d}{s} = \frac{2.5\times 10^{6}}{2.5\times 10^{8}} = 0.01\ s

t = 10 ms

  • In general, propagation time, t is given by:

       t = \frac{link\ distance}{Propagation\ speed}

  • No, this delay is independent of the length of the packet.
  • No, this delay is independent of the rate of transmission.

3 0
4 years ago
Each color is visible light corresponds to a different?
AnnyKZ [126]
Wavelengths and frequecy
8 0
4 years ago
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