2 years ago

Pls help, it’s due today Ba(NO3)2 How many moles of oxygen are in this substance?

Chemistry

1 answer:

Ymorist [56]2 years ago

7 0

Answer:

3.00

Explanation:

Since assuming oxygen as molecule so there are 6 atoms hence 3 molecules of oxygen hence 3 moles

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Calcium nitrate tetrahydrate dissolves in cold water to the extent of 266 g per 100 cm3. What is the concentration of nitrate io

Soloha48 [4]

Answer : The correct option is, (b) 22.5 M

Explanation : Given,

Mass of calcium nitrate tetrahydrate = 266 g

Molar mass of calcium nitrate tetrahydrate = 236.15 g/mole

Volume of solution = $100cm^3=100mL$

Molarity : It is defined as the moles of solute present in one liter of solution.

Formula used :

$Molarity=\frac{\text{Mass of calcium nitrate tetrahydrate }\times 1000}{\text{Molar mass of calcium nitrate tetrahydrate }\times \text{volume of solution in ml}}$

Now put all the given values in this formula, we get:

$Molarity=\frac{266g\times 1000}{236.15g/mole\times 100ml}=11.26mole/L=11.26M$

As calcium nitrate tetrahydrate dissociate to give 1 mole of calcium ion, 2 moles of nitrate ion and 4 moles of water.

The concentration of nitrate ion = $2\times 11.26M=22.5M$

Thus, the concentration of nitrate ion is, 22.5 M

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3 years ago

Does it require more energy to "vaporize" water at the boiling point or to melt water at the melting point? Explain.

sveticcg [70]

Answer:

yes I think so because more heat evaporates water

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2 years ago

What do you already know about the role of water within your body?

Fudgin [204]

Answer:

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3 years ago

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Which of the following changes will decrease the rate of collisions between gaseous molecules oftype A and B in a closed contain

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D - take away B molecules

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3 years ago

A sample of 0.53 g of carbon dioxide was obtained by heating 1.31 g of calcium carbonate. what is the percent yield for this rea

Masja [62]

CaCO3(s) ⟶ CaO(s)+CO2(s)

moles CaCO3: 1.31 g/100 g/mole CaCO3= 0.0131

From stoichiometry, 1 mole of CO2 is formed per 1 mole CaCO3, therefore 0.0131 moles CO2 should also be formed.
0.0131 moles CO2 x 44 g/mole CO2 = 0.576 g CO2

Therefore:
% Yield: 0.53/.576 x100= 92 percent yield

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3 years ago

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