Answer:
The skydiver will fall 1600 ft in 10 seconds.
Step-by-step explanation:
<u>Distance a body falls from rest varies directly as the squares of the time it falls </u>
Let distance = s
time = t
Therefore , s = k ![\times t^{2}](https://tex.z-dn.net/?f=%20%5Ctimes%20t%5E%7B2%7D)
Given, the body falls 64 ft in 2 seconds.
Substituting in above equation,
64 = k ![\times (2)^{2}](https://tex.z-dn.net/?f=%20%5Ctimes%20%282%29%5E%7B2%7D)
64 = k ![\times (4)](https://tex.z-dn.net/?f=%20%5Ctimes%20%284%29%20)
k = ![\frac{64}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B64%7D%7B4%7D)
k = 16 ft/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
We have to find how much he will fall in 10 seconds.
s = k ![\times t^{2}](https://tex.z-dn.net/?f=%20%5Ctimes%20t%5E%7B2%7D)
s = ![16 \times 10^{2}](https://tex.z-dn.net/?f=16%20%5Ctimes%2010%5E%7B2%7D)
s = ![16 \times 100](https://tex.z-dn.net/?f=16%20%5Ctimes%20100)
s = 1600 ft
Answer:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15...
The circumference of the plate 21.98.
This is why because
3.14 x 7 = 21.98
So the circumference is 21.98
Answer and explanation:
The hedging strategy is one where an individual is able to hold two opposing positions such that he is able to protect either position from profit or loss as each move in opposite directions. For example in this situation, if Sue wants to hedge her bets here, she would need to place a bet that there will be a quiz and also place a bet that there will be no quiz. In this way she uses up to $40, $20 for no quiz and $20 for a quiz. If for instance it goes in Torik's favour and there is no quiz, Sue loses $20 but also gets that $20 back. If it goes in Sue's favour, then she makes $60