Materials required for the experiment of limiting force borne by string:-
- String balance
- weights
- light strings
- weight hanger
- pan for spring balance
- Sand
Steps of procedure for for the experiment of limiting force borne by string:-
- First we have to tie a light string to the fixed support and then tie the other end with the weight hanger consists of weight.
- Add additional weight to the hanger again and again. And continue the same until the string is broken.
- Note down the weight (x) where the string is broken.
- Suspend spring balance to a support.
- Tie the light string at the end of the balance and at the other end suspend the pan for spring balance.
- Now place the weights (x-100 grams) in pan.
- Observe the reading in the spring balance.
- Add a small amount of sand in the pan by observing the readings.
- same is to be done till the string is broken.
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Answer:12.28m/s
Explanation:
momentum of baseball =mass of baseball x velocity of baseball
Momentum of baseball =0.31x21
Momentum of baseball =6.51kgm/s
For a softball to have same momentum with the baseball we can say :momentum of baseball =mass of softball x velocity of softball
6.51=0.53 x velocity of softball
Velocity of softball =6.51/0.53
Velocity of softball =12.28m/s
The magnitude of the current in wire 3 is (I₃)= 0.33A
<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>
To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,
I₁ + I₂ + I₃ = 0
Where we are given,
I₁ = current in wire 1
=0.40 A.
I₂ = current in wire 2
= -0.73 A.
We have to calculate the magnitude of the current in wire 3, I₃
Now we put the known values in above equation, we get,
I₁ + I₂ + I₃ = 0
Or, I₃ = -.(I₁ + I₂)
Or, I₃ = -.(0.40 - 0.73)
Or, I₃ = 0.33 A
From the above calculation, we can conclude that the current in wire 3 is I₃ = 0.33 A
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