Question

The sound level measured in a room by a person watching a movie on a home theater system varies from 40 dB during a quiet part to 80 dB during a loud part. Approximately how many times louder is the latter sound

Answer 1

Answer:

$\alpha=-3.01dB$

Explanation:

From the question we are told that:

Sound level intensity

 $\triangle I=40dB-80dB$

Generally the equation for  intensity level  is mathematically given by

 $\alpha=10log_{10}(I/I_x)dB$

Where

 I= Intensity measured

 $I_x=Threshold\ of\ audibility$

 $I_x= 10-12 W / m2$

 $\alpha= 10 log10 \frac{I_1}{I_x} - 10 log10 \frac{}I_2{I_x}$

 $\alpha= 10 log10 \frac{I_1}{I_2}$

 $\alpha=10 log10\frac{40}{80}$

 $\alpha=-3.01dB$