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2 years ago

Explain the mode of operation of x-ray

Physics

2 answers:

Serga [27]2 years ago

7 0

Answer:

If x-rays get in touch with our body tissues, they create a picture of a metal film. The high energizing rays are unable to penetrate soft tissue, such as skin and organs and travel through the laser. The places where the x-rays pass soft tissues are Black areas of an X-ray.

igomit [66]2 years ago

7 0

Answer:

Explanation:

Mode of Operation: In the X-ray tube a Low voltage high p.d is applied between the hot cathode and the anode. Electrons are emitted from the cathode and are accelerated to an extremely high speed. ... They are produced by increasing the p.d. between the cathode and anode.

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Two boxes connected by a light horizontal rope are on a horizontal surface. The coefficient of kinetic fric-tion between each bo

babunello [35]

Answer:

(A). The tension in the rope that connects the boxes is 10.50 N.

(B). The value of m is 7 kg.

Explanation:

Given that,

Mass of box B = 5.00 kg

Mass of box A = m

Force = 40.0 N

Direction= 53.1°

Acceleration = 1.50 m/s²

Coefficient of kinetic friction = 0.30

(A). We need to calculate the tension in the rope that connects the boxes

Using balance equation

$T=ma+m\cos\theta$

Put the value into the formula

$T=5\times1.50+5.00\cos53.1$

$T=10.50\ N$

(B). We need to calculate the value of m

Using formula of tension

$T=ma$

$m=\dfrac{T}{a}$

Put the value into the formula

$m=\dfrac{10.50}{1.50}$

$m=7\ kg$

Hence, (A). The tension in the rope that connects the boxes is 10.50 N.

(B). The value of m is 7 kg.

3 0

3 years ago

A light-year is the distance that light travels in one year. The speed of light is 3.00 × 108 m/s. How many miles are there in o

Alinara [238K]

Answer:

(a) $5.88\times 10^{12}mi$

Explanation:

We have given speed of light $c=3\times 10^8m/sec$

Given time = 1 year =365 days

We know that in 1 minute = 60 sec

1 hour = 60×60 = 3600 sec

In one day = 24 hour = 24×60×60=86400 sec

So in 365 days = 365×86400 $=3.1536\times 10^7sec$

We know that distance = speed ×time $=3.1536\times 10^7\times 3\times 10^8=9.46\times 10^{15}m$

We have given that 1 mi = 1609 m

So $9.46\times 10^{15}m=\frac{9.46\times 10^{15}}{1609}=5.88\times 10^{12}mi$ So option (a) is correct

8 0

3 years ago

A cube of wood having an edge dimension of 20.0cm and a density of 650 kg /m³ floats on water. (b) What mass of lead should be p

schepotkina [342]

The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.

<h3>What mass of lead should be placed on the cube?</h3>

Given: Side of the cube (a) = 20cm

The density of the cube (ρc) = $$$650 kg/m^3$

a) Applying the force balance, the buoyant force must be equal to the weight of the cube

ρcgV = ρg × (Ax)

Substituting the values in the above equation, we get

$(650*(0.2 m)^3)=1000*(0.2 m)^2*x$

x = 0.13

where x is the height of the cube in the water

$$$A = a^2$ is the area of the cross-section

ρ is the density of the water

V is the volume of the cube

Now, the height above the surface of the water would be

h = a − x

Substituting the values, then we get

h = 0.2 − 0.13

h = 0.07 m

b) The mass added is "m" so the complete cube is submerged in the water, therefore

ρcgV + mg = ρg × (V)

$$(650*(0.2 m)^3)+m=1000*(0.2 m)^3$

m = 2.8 kg

The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.

To learn more about buoyant force refer to:

brainly.com/question/11884584

#SPJ4

7 0

1 year ago

What will happen if more solute is added than can be dissolved .

zysi [14]

The solute would then sink to the bottom and would not dissolve

3 0

3 years ago

A neutron star has a mass of between 1.4-2.8 solar masses compressed to the size of:

BARSIC [14]

The correct answer is D. An average city

Explanation:

A neutron star differs from others due to its massive density, this means a lot of matter is compressed in a small area. Indeed, neutron stars have a mass of around 1.4 to 2.8 times the mass of the sun. But these are considerably small as they only measure around 20 kilometers, which is the size of an average city. Additionally, neutron stars are this dense because they are the result of a regular star exploding, which leads to a super-dense core, or neutron star. In this context, the mass of a neutron star is compressed to the size of an average city.

7 0

3 years ago

Explain the mode of operation of x-ray​

Explain the mode of operation of x-ray