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2 years ago

Explain the mode of operation of x-ray

Physics

2 answers:

Serga [27]2 years ago

7 0

Answer:

If x-rays get in touch with our body tissues, they create a picture of a metal film. The high energizing rays are unable to penetrate soft tissue, such as skin and organs and travel through the laser. The places where the x-rays pass soft tissues are Black areas of an X-ray.

igomit [66]2 years ago

7 0

Answer:

Explanation:

Mode of Operation: In the X-ray tube a Low voltage high p.d is applied between the hot cathode and the anode. Electrons are emitted from the cathode and are accelerated to an extremely high speed. ... They are produced by increasing the p.d. between the cathode and anode.

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Please need help on this

Vera_Pavlovna [14]

Answer:

i have no idea

Explanation:

it could be B. but i dont belive in myself sooooooooooo.....ehhhh yeah

4 0

2 years ago

a person when asked to speak up,increases her sound level from 30dB to 60dB.The amount of power per unit area increased by? a)30

aivan3 [116]

Answer:

d) 1000 times

Explanation:

As we know that difference of sound level is given as

$L_2 - L_1 = 10 Log \frac{I_2}{I_1}$

so here we need to find the ratio of two intensity

it is given as

$Log\frac{I_2}{I_1} = \frac{(L_2- L_1)}{10}$

$Log\frac{I_2}{I_1} = \frac{60 - 30}{10}$

$Log\frac{I_2}{I_1} = 3$

now we have

$\frac{I_2}{I_1} = 10^3$

so it is

d) 1000 times

4 0

2 years ago

Which statement best compares the momentum of a 5-kilogram fish swimming at a speed of 10 meters/second and a 2-kilogram fish sw

ruslelena [56]

M = mass of the larger fish =5kg
V = velocity of the larger fish =10m/s
m = mass of the smaller fish =2kg
v = velocity of the smaller fish =10m/s
formula=
MV = mv
5kg*10m/s=2kg*10m/s
biggern mass fish has more momentum
hope this helps

6 0

2 years ago

Read 2 more answers

so i had to work for halloween, my first Halloween working. When i got home my lil bro showed me all the candy he collected so i

Mrrafil [7]

Answer:

now that's a sweet little bro

4 0

2 years ago

Read 2 more answers

A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on

MAXImum [283]

Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

$Ec=\frac{1}{2} *m*v^{2}$