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3 years ago

What is the best description of the chromosomes by the end of metaphase of mitosis?

Physics

1 answer:

s344n2d4d5 [400]3 years ago

8 0

I did the test and the anwser is d- the chromosome pairs collect in a line across the middle of the cell

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You drive on Interstate 10 from San Antonio to Houston, half the time at 54 km/h and the other half at 118 km/h. On the way back

Irina-Kira [14]

Answer:

Average speed: 86 km/h

Explanation:

Driving from San Antonio to Houston:

1st. half time: 54km/h

2nd. half time: 118 km/h

Average speed = [tex] \frac{54 \frac{km}{h}+ 118 \frac{km}{h} }{2}=86 \frac{km}{h} [\tex]

Driving way back:

1st. half time: 54km/h

2nd. half time: 118 km/h

Average speed = [tex] \frac{54 \frac{km}{h}+ 118 \frac{km}{h} }{2}=86 \frac{km}{h} [\tex]

As in both routes we have the same average speed, then the average speed for the whole trip is 86 km/h

7 0

3 years ago

Read 2 more answers

How does mass affect weight?

devlian [24]

Answer: Mass affects the weight of an object with the effects of gravity.

Weight is the measure of the force of gravity on an object's mass, while mass is the measure of how much matter there is in an object.

5 0

2 years ago

A softball with a mass of 0.11 kg goes moves at a speed of 12 m/s, then the ball is hit by a bat and rebounds in the opposite di

dimulka [17.4K]

=1244 and that's from my math book

7 0

2 years ago

a runner covers the last straight stretch of the race in 4 s. durning that time, he speeds up from 5 m/s to 9m/s what is the run

Sergio039 [100]

Answer:

The runner's acceleration was $1\ m/s^2$

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

$v_f=v_o+at$

Solving for a:

$\displaystyle a=\frac{v_f-v_o}{t}$

The runner speeds up from vo=5 m/s to vf=9 m/s in t=4 seconds, thus:

$\displaystyle a=\frac{9-5}{4}$

$\displaystyle a=\frac{4}{4}=1$

The runner's acceleration was $1\ m/s^2$

5 0

3 years ago

After robbing a bank, a criminal tries to escape from the police by driving at a constant speed of 55 m/s (about 125 mph). A pol

vfiekz [6]

Answer:

18.03 s

Explanation:

We have two different types of motions, the criminal moves with uniform motion while the police do it with uniformly accelerated motion. Therefore we will use the equations of these cases. We know that by the time the police reach the criminal they will have traveled the same distance.

$x=vt\\x=x_{0}+v_{0}t+\frac{a}{2}t^2$

The distance between the police and the criminal when the first one starts the persecution is 0, its initial speed is also zero. So:

$x=(55m/s)t\\x=\frac{6.1m/s^2}{2}t^2=(3.05m/s^2)t^2$

Equalizing these two equations and solving for t:

$(55m/s)t=(3.05m/s^2)t^2\\(3.05m/s^2)t^2-(55m/s)t=0\\t((3.05m/s^2)t-55m/s)=0\\t=0 \\(3.05m/s^2)t-55m/s=0\\t=\frac{55m/s}{3.05m/s^2}=18.03 s$

6 0

2 years ago