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3 years ago

Ammonia is produced by the chemical reaction of hydrogen and nitrogen

Chemistry

1 answer:

MaRussiya [10]3 years ago

6 0

Answer:

3.6 mol H₂

Explanation:

N₂ + 2H₂ → 2NH₃

In order to convert from N₂ moles to H₂ moles we need to use a conversion factor. This conversion factor has to have<u> N₂ moles in the denominator and H₂ moles in the numerator</u>, using the <em>stoichiometric coefficients</em> of the reaction, as follows:

1.8 mol N₂ * $\frac{2molH_2}{1molN_2}$ = 3.6 mol H₂

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The pH of lemon juice is 2, and the pH of orange juice is 4. Which of these is more acidic, and by how much? What does this mean

katovenus [111]

Explanation:

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3 years ago

balu736 [363]

Explanation:

Given -

An organic compound gives H₂ gas with Na
On treatment with alkaline iodine it gives yellow ppt.
On oxidation with CrO₃/H⁺ forms an aldehyde (C₂H₄O)

To Find -

Name the compound and write the reaction involved

Now,

Let A be the organic compound.

Then,

A + Na → + H₂↑
A + I₂ → CHI₃ (yellow ppt.)
A + CrO₃ + H⁺ → C₂H₄O

Now,

Here we see that compound A reacts with chromic oxide (CrO₃) in the presence of acidic medium gives aldehyde.

Functional group of aldehyde = —CHO

And It forms only 2 Carbon aldehyde it means, It is Ethanal (CH₃CHO).

Compound A reacts with chromic oxide (CrO₃) in the presence of acidic medium gives ethanal.

It means,

We know that 1° alcohol on oxidation gives aldehyde.

Here it gives 2 Carbon aldehyde.

It means,

Here 2 Carbon and 1° alcohol is used.

Now,

Its cleared that Compound A is Ethanol.

Reaction Involved -

CH₃CH₂OH + Na → CH₃CH₂O⁻Na⁺ + H₂↑
CH₃CH₂OH + I₂ + OH⁻ → CHI₃↓ + HCOO⁻ + HI + H₂O
CH₃CH₂OH + CrO₃ + H⁺ → CH₃CHO

6 0

3 years ago

Baking soda (NaHCO3) and vinegar (HC2H3O2) react to form sodium acetate, water, and carbon dioxide. If 42.00 g of baking soda re

Setler [38]

Answer:

0.5 mole of CO₂.

Explanation:

We'll begin by calculating the number of mole in 42 g of baking soda (NaHCO₃). This can be obtained as follow:

Mass of NaHCO₃ = 42 g

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 23 + 1 + 12 + 48

= 84 g/mol

Mole of NaHCO₃ =?

Mole = mass / molar mass

Mole of NaHCO₃ = 42/84

Mole of NaHCO₃ = 0.5 mole

Next, balanced equation for the reaction. This is given below:

NaHCO₃ + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O + CO₂

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂

Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.

Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.

Thus, 0.5 mole of CO₂ was obtained from the reaction.

7 0

3 years ago