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enyata [817]
2 years ago
8

Choose all options that apply . Which of the following are steps necessary to ensure patient safety ? a) Make sure that the medi

cation is dispensed in the same units in which it was prescribed. b ) Review any calculation questions with the pharmacist . Check to see if there's a better medication for the patient's problem. d) Dispense an extra dose to save the patient from having to return in case of loss or damage to one of the doses. Oe ) Compare the label on the medication with the order from the physician .
Chemistry
1 answer:
Tems11 [23]2 years ago
4 0

Answer:

c) Check to see if there's a better medication for the patient's problem.

d) Dispense an extra dose to save the patient from having to return in case of loss or damage to one of the doses.

e ) Compare the label on the medication with the order from the physician .

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Five students performed a Kjeldahl nitrogen analysis of a protein sample. The following weight % nitrogen values were determined
Sunny_sXe [5.5K]

Answer:

G_calculated = 1.756

The outlier should be rejected, as G_cal > G_tab (= 1.463) at 95 % confidence.

Explanation:

The Grubb's test is used for identifying an outlier in data, which is from the same population. For this, a statistical term, G, is calculated for the suspected outlier. If the calculated value is greater than the tabulated G value then the suspected value is rejected. This term is given as,

G_calculated = | suspect value - mean| / s

Here,  suspect value is 13.8, mean is to be taken of all the data (including suspected value). s is the standard deviation of the sample data.

s is calculated from the following formula:

s = (Σ(xi - x)²/(N-1))^1/2

Here, x is the mean, which is 15.24, xi is individual value and N is the total number of data (5).

From the above formula, s is found to be

Standard Deviation, s = 0.820

Now for G value,

G_calculated = | 13.8 - 15.24| / (0.820)

G_ calculated = 1.756

The tabulated G value at 95 % confidence and N -1 (5 - 1 = 4) degree of freedom is, 1.463.

As calculated G (1.756) is greater than the tabulated G (1.463), the value 13.8 is considered an outlier at 95 % confidence.  

3 0
3 years ago
A disturbance in matter that carries energy from one place to another is called
siniylev [52]
The answer you're looking for is: a wave.
6 0
3 years ago
PLZ HELP. Write and balance the following chemical equations:
zubka84 [21]

Answer:

No they form nitrogen oxide which can be poisonous to some species but depending on the amount of nitrogen it can be harmful to everything living. Such as if you put it with a plant that had low nitrogen levels then there would be no carbon dioxide to filter.

Explanation:

6 0
3 years ago
Generally, systems move spontaneously in the direction of increasing entropy. TRUE FALSE
allochka39001 [22]

Answer:

true

Explanation:

5 0
3 years ago
A. The half-life for a first order reaction in 49 minutes. What is the rate constant?B.For a second order reaction, the half-lif
Burka [1]

Answer:

a) 0,014 min⁻¹

b) 1452 seconds.

c) 0,02156 M

d) The faster rate is for the reaction A. The largest rate constant, k, is for A reaction

Explanation:

a) For a first order reaction the half-life is:

t_{1/2} = \frac{ln(2)}{k} <em>(1) </em>As half.life is 49 min. Rate constant -k- is: 0,014 min⁻¹

b) The half-life is defined as the time that takes in descompose the half of the initial concentration of a compound.

As half-life is 726s. In 726s the concentration will be 0,300M, In the next 726s the concentration will be 0,150M. Thus, thae time it takes to decrease concentration until 0,150M is 726s×2= 1452 seconds

c) In the same way, 11072 years are 4 half-life for this reaction, thus:

0,345M/2⁴ = 0,02156 M

d) By definition of half-life, the less half-life, the faster rate. Thus, The faster rate is for the reaction A.

By (1) half-life is inversely proportional to rate constant. Thus, the less half-life, the largest rate constant. The largest rate constant, k, is for A reaction

I hope it helps!

7 0
3 years ago
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