Answer:
The pOH of HNO₃ solution that ha OH⁻ concentration 9.50 ×10⁻⁹M is 8.
Explanation:
Given data:
[OH⁻] = 9.50 ×10⁻⁹M
pOH = ?
Solution:
pOH = -log[OH⁻]
Now we will put the value of OH⁻ concentration.
pOH = -log[9.50 ×10⁻⁹M]
pOH = 8
Thus the pOH of HNO₃ solution that ha OH⁻ concentration 9.50 ×10⁻⁹M is 8.
Planck suggested that light/energy was absorbed/released in certain amounts, called quanta.

what is the chemical formula of (Sodium hydroxide ) ??
<h3> ⚘ NaOH</h3>
- Sodium hydroxide, Sodium oxidanide


Ground state means 1s which can hold 2 electrons.
l for 1s is = 0
ml = 0 (given)
possible values of m = 0
so it can hold maximum of 2 electrons. One spin up and other spin down.
The conversion of 2 - butanol to 2 - nitrobutane involves conversion of 2 butanol to 2 - bromobutane and subsequently to 2 - nitrobutane.
In order to convert 2 - butanol to 2 - nitrobutane, an SN2 reaction is first carried out in which 2 - butanol is converted to 2 - bromobutane. This reaction proceeds with inversion of configuration at the chiral carbon as expected.
This product is subsequently reacted with silver nitrite in ethanol to yield 2 - nitrobutane along side silver bromide. Some alkyl nitrite is also produced as a by product. The components of the mixture are separated by fractional distillation. The scheme of the reaction is shown in the image attached to this answer. This reaction is only applied to primary and secondary alkyl halides.
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