All categories

3 years ago

What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?

Chemistry

1 answer:

Vsevolod [243]3 years ago

7 0

The dilution formula can be used to find the volume needed

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

c1 - 0.33 M

c2 - 0.025 M

v2 - 25 mL

Substituting these values in the equation

0.33 M x v1 = 0.025 M x 25 mL

v1 = 1.89 mL

Therefore 1.89 mL of the 0.33 M solution needs to be diluted up to 25 mL to make a 0.025 M solution

You might be interested in

A 100 W light bulb is placed in a cylinder equipped with a moveable piston. The light bulb is turned on for 2.0×10−2 hour, and t

drek231 [11]

Answer:

(a) ΔU = 7.2x10²

(b) W = -5.1x10²

(c) q = 5.2x10²

Explanation:

From the definition of power (p), we have:

$p = \frac {\Delta W}{\Delta t} = \frac {\Delta U}{\Delta t}$ (1)

where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s)

(a) We can calculate the energy (ΔU) using equation (1):

$\Delta U = p \cdot \Delta t = 100 \frac{J}{s} \cdot 2.0\cdot 10^{-2} h \cdot \frac{3600s}{1h} = 7.2 \cdot 10^{2} J$

(b) The work is related to pressure and volume by:

$\Delta W = -p \Delta V$

where p: pressure and ΔV: change in volume = V final - V initial

$\Delta W = - p \cdot (V_{fin} - V_{ini}) = - 1.0 atm (5.88L - 0.85L) = - 5.03 L \cdot atm \cdot \frac{101.33J}{1 L\cdot atm} = -5.1 \cdot 10^{2} J$

(c) By the definition of Energy, we can calculate q:

$\Delta U = \Delta W + \Delta q$

where Δq: is the heat transfer

$\Delta q = \Delta U - \Delta W = 7.2 J - (-5.1 \cdot 10^{2} J) = 5.2 \cdot 10^{2} J$

I hope it helps you!

6 0

4 years ago

What information does Jaime need to evaluate the accuracy of his calculation?

Effectus [21]

Answer:

well we can't awnser this we don't have the full information srry♥️✨

4 0

4 years ago

Read 2 more answers

How are h2o and NaCL different

MAVERICK [17]

Answer:

1. H2O is a covalent bond, NaCl is an ionic bond

2. H2O uses hydrogen bonding (H-bonds), NaCl does not

3. H2O is liquid at room temperature. NaCl is solid.

Explanation:

3 0

3 years ago

Sodium (na), atomic number 11, has a tendency to lose an electron in the presence of chlorine. after losing the electron, na has

Paha777 [63]

Eleven because protons don’t leave.

3 0

3 years ago

Enzymes work by _____. enzymes work by _____. decreasing the potential energy difference between reactant and product adding ene

Anton [14]

The appropriate answer is they decrease the potential energy difference between reactant and product. They do this by bringing products and reactants together at the active site on the enzyme molecule. Enzymes are biological catalysts. They increase the rate of a chemical reaction without being used up in the reaction itself. So one molecule of an enzyme is used many times to catalyze the reaction of other molecules.

7 0

3 years ago