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natta225 [31]
3 years ago
8

What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?

Chemistry
1 answer:
Vsevolod [243]3 years ago
7 0

The dilution formula can be used to find the volume needed

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

c1 - 0.33 M

c2 - 0.025 M

v2 - 25 mL

Substituting these values in the equation

0.33 M x v1 = 0.025 M x 25 mL

v1 = 1.89 mL

Therefore 1.89 mL of the 0.33 M solution needs to be diluted up to 25 mL to make a 0.025 M solution

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select the equations that are correctly balanced. h2o 2o2? h2o2 fe2o3 3h2? 2fe 3h2o al 3br2? albr3 caco3? cao co2 can you clarif
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The correct answers would be the second and the last option. The equations that are correctly balanced are:

</span> fe2o3 + 3h2 = 2fe + 3h2o 
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To balance, it should be that the number of atoms of each element in the reactant and the product side is equal.
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