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Artemon [7]
2 years ago
10

How much of a 400g sample remains after 4 years if a radioactive isotope has a half-life of 2 years?

Chemistry
1 answer:
timama [110]2 years ago
3 0

Answer:

100 g

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 400 g

Time (t) = 4 years

Half-life (t½) = 2 years

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Time (t) = 4 years

Half-life (t½) = 2 years

Number of half-lives (n) =?

n = t / t½

n = 4 / 2

n = 2

Thus, 2 half-lives has elapsed.

Finally, we shall determine the amount remaining of the radioactive isotope. This can be obtained as follow:

Original amount (N₀) = 400 g

Number of half-lives (n) = 2

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2² × 400

N = 1/4 × 400

N = 0.25 × 400

N = 100 g

Thus, the amount of the radioactive isotope remaing is the 100 g.

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elixir [45]
The tree I know is producer
7 0
2 years ago
Write the chemical formula for sodium hypobromite.
irga5000 [103]

Answer:

             NaOBr  (or)  Na⁺ ⁻OBr

Explanation:

The Oxo-Acids of Bromine are as follow,

                           Hypobromous Acid  =  HOBr

                           Bromous Acid  =  HOBrO

                           Bromic Acid  =  HBrO₃

                           Perbromic Acid  =  HBrO₄

When these acids are converted to their conjugate bases their names are as follow,

                           Hypobromite  =  ⁻OBr

                           Bromite  =  ⁻OBrO

                           Bromate  =  ⁻OBrO₂

                           Perbromate  =  ⁻OBrO₃

According to rules, the positive part of ionic compound is named first and the negative part is named second. So, Sodium Hypobromite has a chemical formula of Na⁺ ⁻OBr or NaOBr.

6 0
2 years ago
The following equation is balanced according to the Law of Conservation of Mass:
igor_vitrenko [27]
The answer would be:
True
6 0
2 years ago
A piece of metal that has a density of 5.2 g/cm3 and a mass of 100 g was placed in a full jar of water. How many mL of water was
Klio2033 [76]

Answer:

100g / (5.2g/cm3)

= 100g / (5.2g / 1cm3)

= 100g x 1cm3 / 5.2 g

= 19.2 cm3

Since 1 cm3 = 1 ml, your answer is 19.2 ml.

5 0
3 years ago
If 10.57 g of magnesium reacts completely with 6.96 g of oxygen, what is the percent by mass of oxygen in magnesium oxide? Round
Deffense [45]

Answer:

39.7 %

Explanation:

magnesium + oxygen ⟶ magnesium oxide

   10.57 g         6.96 g               17.53 g

According to the <em>Law of Conservation of Mass</em>, the mass of the product must equal the total mass of the reactants.

Mass of MgO = 10.57 + 6.96

Mass of MgO = 17.53 g

The formula for mass percent is

% by mass = Mass of component/Total mass × 100 %

In this case,

% O = mass of O/mass of MgO × 100 %

Mass of O = 6.96 g

Mass of MgO = 17.53 g

% O = 6.96/17.53 × 100

% O = 0.3970 × 100

% O = 39.7 %

5 0
3 years ago
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