Answer:
0.1127 grams of Mg is used to produce one gram of silver
Explanation:
Write a balanced equation
Mg(s) +2Ag + (aq) --> (aq) + 2Ag(s)
The atomic mass of magnesium is 24.31 g/mol and the atomic mass of silver is 107.84g/mol
1 g Ag of silver is produced from [(1 mol Mg)(24.31 g/mol)] /[ (2mol Ag)(107.84g/mol)]
1 g Ag of silver is produced from 0.1127 grams of Mg
0.1127 grams of Mg is used to produce one gram of silver
The last statement is correct...
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There are 0.400 mol Br₂ in the sample..
Mass of Br₂ = 20.5 mL Br₂ × 3.12 g Br₂/1 mL Br₂ = 63.96 g Br₂.
Moles of Br₂ = 63.96 g Br₂ × (1 mol Br₂/159.81 mol Br₂) = 0.400 mol Br₂
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