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Schach [20]
2 years ago
9

Un vehículo parte del reposo y acelera constantemente a 6 m/s2

Physics
1 answer:
grin007 [14]2 years ago
4 0
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How did Marie Curie’s research in radioactivity benefit others while harming her
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 <span>The discoveries Mme Curie made were of great benefit to physics, chemistry and medicine. During the time she was doing her research, the health effects of ionizing radiation were not known. The amount of radiation that she was exposed to led to her death. Even today her notebooks and other personal effects are highly contaminated with radioactive material. 
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5 0
3 years ago
Four wires meet at a junction. In two of the wires, currents and enter the junction. In one of the wires, current leaves the jun
Vera_Pavlovna [14]

Answer:

Explanation:

Kirchoff's current law: It states that the total current entering at a junction is equal to the total current leaving at the junction. It isbased on conservation of charge.  

As two current i1 and i2 is entering at the junction and i3 is leaving, so the current in forth wire is

i4 = i1 + i2 - i3

4 0
3 years ago
The Lamborghini Huracan has an initial acceleration of 0.80g. Its mass, with a driver, is 1510 kg. If an 80 kg passenger rode al
irina [24]

Answer:

a = 15.1 g

Explanation:

The relation between mass and acceleration is given by :

m\propto \dfrac{1}{a}

If a₁ = 0.80g, m₁ = 1510 kg, m₂ = 80 kg, we need to find a₂

So,

\dfrac{m_1}{m_2}=\dfrac{a_2}{a_1}\\\\a_2=\dfrac{a_1m_1}{m_2}\\\\a_2=\dfrac{0.8g\times 1510}{80}\\\\a_2=15.1g

So, the car's acceleration would be 15.1 g.

6 0
3 years ago
What’s the net force of an object being throwing into the air
timurjin [86]

Answer: forces acting on an object being thrown into the air is gravity and possibly air resistance

Explanation:

4 0
3 years ago
The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that
pav-90 [236]

Answer:

The permittivity of rubber is  \epsilon  = 8.703 *10^{-11}

Explanation:

From the question we are told that

     The  magnitude of the point charge is  q_1 =  70 \ nC  =  70 *10^{-9} \  C

      The diameter of the rubber shell is  d = 32 \ cm  =  0.32 \ m

       The Electric field inside the rubber shell is  E =  2500 \ N/ C

The radius of the rubber is  mathematically evaluated as

              r =  \frac{d}{2} =  \frac{0.32}{2}  =  0.16 \ m

Generally the electric field for a point  is in an insulator(rubber) is mathematically represented as

         E =  \frac{Q}{ \epsilon }  *  \frac{1}{4 *  \pi r^2}

Where \epsilon is the permittivity of rubber

    =>     E  *  \epsilon  *  4 * \pi *  r^2 =  Q

   =>      \epsilon  =  \frac{Q}{E *  4 *  \pi *  r^2}

substituting values

            \epsilon  =  \frac{70 *10^{-9}}{2500 *  4 *  3.142 *  (0.16)^2}

            \epsilon  = 8.703 *10^{-11}

7 0
3 years ago
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