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trasher [3.6K]
3 years ago
14

What is the value of acceleration as a body moves with an uniform speed

Physics
1 answer:
Levart [38]3 years ago
4 0

Answer:

the value of acceleration as a body moves with an uniform speed is zero

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A spherical mirror is polished on both sides. When the concave side is used as a mirror, the magnification is 4.4. What is the m
patriot [66]

Answer:

m = \frac{-4.4}{7.4}

Explanation:

magnification is the ratio of distance of image to distance of object

i.e. m = -\frac{d_i}{d_o}

d_i = -4.4 d_o

As per the lens equation,

\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f}

We will calculate the focal length of the mirror

\frac{1}{yd_o} + \frac{1}{-4.4d_o} = \frac{1}{f} \\\frac{4.4 -1}{4.4} \frac{1}{d_o} =  \frac{1}{f}\\f = \frac{4.4}{3.4}  d_o

Now for convex mirror only the sign will change

Thus, focal length would be equal to

f = - \frac{4.4}{3.4} d_o

Plugging this value into lens equation, we get

\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f} \\\frac{1}{d_o} + \frac{1}{d_i} = \frac{-3.4}{4.4} \frac{1}{d_o} \\\frac{7.4}{4.4} \frac{1}{d_o} = \frac{1}{d_i}\\\frac{d_i}{d_o} = \frac{4.4}{7.4} \\m =-  \frac{d_i}{d_o} \\\\m = - \frac{4.4}{7.4}

8 0
3 years ago
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
Paladinen [302]

Answer:

1.  λ = 5.60 m , 2.  T = 5.80 s  3.  v = 0.966 m/s   4.  A = 0.315 m

Explanation:

1. The definition of wavelength is the distance between two consecutive maximums or minimums, so that the wave is repeated, in this case they give us the distance between two consecutive maximums, therefore

    λ = 5.60 m

2. the period is the time it takes for the wave to start repeating itself, going through the same point. They give time to go from the highest point to the lowest point, which is the time for half a wavelength, so the time for a wavelength is

     T = 2 t

     T = 2 2.90

     T = 5.80 s

3. For all waves the speed is the product of the wavelength by the frequency and the frequency is the inverse of the period

    v = λ f

    f = 1 / T

   v =  λ / T

   v = 5.60 / 5.80

   v = 0.966 m / s

4. The amplitude of the wave is the value of the zero displacement point to the maximum displacement point, give the value between the maximum and minimum displacement

     A = d / 2

     A = 0.63 / 2

     A = 0.315 m

8 0
3 years ago
What are the five advantages of using machine and tools in our daily life?​
daser333 [38]

Answer:

it makes our work easy and

time saving

it multiply our force applied

it complete our work with high efficiency

by using this,less effort is required for the work.

7 0
3 years ago
At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people o
velikii [3]
Let s = rate of rotation 
<span>Let r = radius of earth = 6,400km </span>
<span>Then solving (s^2) r = g will give the desired rate, from which length of day is inferred. </span>
<span>People would not be thrown off. They would simply move eastward in a straight line while the curved surface of earth fell away from beneath them.</span>
5 0
3 years ago
Read 2 more answers
A ball is thrown vertically downwards with a speed 7.3 m/s from the top of a 51 m tall building. With what speed will it hit the
ddd [48]

Answer:

32.46m/s

Explanation:

Hello,

To solve this exercise we must be clear that the ball moves with constant acceleration with the value of gravity = 9.81m / S ^ 2

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are the follow

\frac {Vf^{2}-Vo^2}{2.a} =X

Where

Vf = final speed

Vo = Initial speed =7.3m/S

A = g=acceleration =9.81m/s^2

X = displacement =51m}

solving for Vf

Vf=\sqrt{Vo^2+2gX}\\Vf=\sqrt{7.3^2+2(9.81)(51)}=32.46m/s

the speed with the ball hits the ground is 32.46m/s

8 0
3 years ago
Read 2 more answers
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