Answer:
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Explanation:
Terminal velocity is given by:

Here, m is the mass of the falling object, g is the gravitational acceleration,
is the drag coefficient,
is the fluid density through which the object is falling, and A is the projected area of the object. in this case the projected area is given by:

Recall that drag coefficient for a horizontal skydiver is equal to 1 and air density is
.

Without drag contribution the motion of the person is an uniformly accelerated motion, thus:

Answer:
The acceleration of the body, a = 2193 m/s²
Explanation:
Given,
The mass of the body, m = 0.3 kg
The force acting on the body, F = 657.9 N
The force acting on an object is proportional to the product of mass and acceleration of the body.
F = m x a
Therefore, the acceleration of the body is
a = F / m
= 657.9 N / 0.3 kg
= 2193 m/s²
Hence, the acceleration of the body, a = 2193 m/s²
In a stationary situation, the weight of person is

This is the weight "felt" by the scale, which is basically the normal reaction applied by the scale on the person, and which uses the value of g (9.81) as reference to convert the weight (602.8 N) into a mass (62 kg).
When the person is in the elevator, the scale says 77 kg. The scale is still using the same value of conversion (9.81), so the apparent weight "felt" by the scale is

This is the normal reaction applied by the scale on the person, and which is directed upward. Besides this force, there is still the weight W of the person, acting downward. So, if we use Newton's second law:


where a is the acceleration of the elevator. If we solve for a, we find

The negative sign means the acceleration is in the opposite direction of g (which we take positive), so it means the elevator is going upward.

The equivalent gravitational force is ~

We know that ~

where,
= mass of 1st object = 500 kg
= mass of 2nd object = 20kg
- G = gravitational constant =

- r = distance between the objects = 2.12 m
Let's calculate the force ~