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Nutka1998 [239]
3 years ago
15

You toss a conductive open ring of diameter d = 1.75 cm up in the air. The ring is flipping around a horizontal axis at a rate o

f 6.25 flips per second. One flip is a full rotation. At your location, the earth's magnetic field is B e = 30.5 μT. What is the maximum emf induced in the ring?
Physics
1 answer:
Mama L [17]3 years ago
8 0

Answer:

The maximum emf induced in the ring

= (2.882 × 10⁻⁷) V

Explanation:

According to the law of electromagnetic induction, the emf induced in the ring is given by

E = N BA w sin wt

The maximum emf induced is

E = N BA w

B = 30.5 μT = (30.5 × 10⁻⁶) T

A = (πD²/4)

D = 1.75 cm = 0.0175 m

A = (π×0.0175²/4) = 0.000240625 m²

Nw = 2π × 6.25 = 39.29 rad/s

E = 30.5 × 10⁻⁶ × 0.000240625 × 39.29

E = (2.882 × 10⁻⁷) V

Hope this Helps!!!

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Answer:

1200\ \text{N}

Explanation:

F = Force on the skier = 60 N

\mu = Coefficient of friction = 0.05

w = Weight of skier

Force is given by

F=\mu w

\Rightarrow w=\dfrac{F}{\mu}

\Rightarrow w=\dfrac{60}{0.05}=\dfrac{6000}{5}

\Rightarrow w=1200\ \text{N}

Weight of the skier on which the force is being applied is 1200\ \text{N} .

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3 years ago
Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is
ipn [44]
F = kq1q2/r^2 

<span>q1 is first charge </span>
<span>q2 is second charge </span>
<span>k is 9 E9 </span>
<span>r is distance between them </span>

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3 years ago
What is thought to make the earth behave as if it contained a huge bar magnet?
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A large amount of molten magnetic material containing Iron is believed to rotate (as a liquid) in the Earth’s core.
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A fish-tank heater is rated at 96 W when connected to 120 V. The heating element is a coil of Nichrome wire. When uncoiled, the
nexus9112 [7]

Answer:

0.232 mm.

Explanation:

Power, P = 96 W

Voltage, V = 120 V

Length of wire, l = 4.2 m

Let r be the radius of the wire.

Resistivity of nichrome, ρ = 1.5 x 10^-6 ohm metre

P = V^2 / R

R = 120 x 120 / 96 = 150 ohm

R = \rho \frac{l}{A}=\rho \frac{l}{\pi r^{2}}

r^2= \rho \frac{l}{\pi \times R}

r^2= \1.5\times10^{-6} \frac{4.2}{3.14 \times 150}

r = 1.16 x 10^-4 m

Diameter = 2 x r = 2 x 1.16 x 10^-4 = 2.32 x 10^-4 m = 0.232 mm

Thus, the diameter of the wire is 0.232 mm.

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What is the wavelength of a wave?
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Definition: Wavelength can be defined as the distance between two successive crests or troughs of a wave.

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