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3 years ago

What is the gravitational force between two identical 5000 kg asteroids whose centers of mass are seperated by 100 m?

1 answer:

7 0

For this question we use the Newtonian relationship F = GMm/r^2.

We often use this relationship when describing one small object orbiting a much more massive one, such as the moon orbiting the Earth. In that case it is obvious that the Earth's mass is M, and the moon's mass is m. In reality it isn't extremely important anyway, but in the case of two identical masses we would ignore the convention.

So, where G is the universal gravitational constant, M = m = 5000kg, and r is the distance between the centres of mass of the two asteroids (100m):

F = GMm/r^2 = (6.67*10^-11)(5000)(5000)/(100^2) = 1.67*10^-7 N.

This answer is to three significant figures. I hope this helps you :)

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Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerate

maria [59]

Complete Question

Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?

Answer:

Go-cart A is faster

Explanation:

From the question we are told that

The length of the track is $l = 1.0 \ km = 1000 \ m$

The speed of A is $v__{A}} = 20 \ m/s$

The uniform acceleration of B is $a__{B}} = 0.333 \ m/s^2$

Generally the time taken by go-cart A is mathematically represented as

$t__{A}} = \frac{l}{v__{A}}}$

=> $t__{A}} = \frac{1000}{20}$

=> $t__{A}} = 50 \ s$

Generally from kinematic equation we can evaluate the time taken by go-cart B as

$l = ut__{B}} + \frac{1}{2} a__{B}} * t__{B}}^2$

given that go-cart B starts from rest u = 0 m/s

$1000 = 0 *t__{B}} + \frac{1}{2} * 0.333 * t__{B}}^2$

=> $1000 = 0 *t__{B}} + \frac{1}{2} 0.333 * t__{B}}^2$

=> $t__{B}} = 77.5 \ seconds$

Comparing $t__{A}} \ and \ t__{B}}$ we see that $t__{A}}$ is smaller so go-cart A is faster

3 0

2 years ago

The force of an electric field is proportional to to electric charge? True or False

tamaranim1 [39]

Answer:True

Explanation:

3 0

3 years ago

Read 2 more answers

A boy 12.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the i

miss Akunina [59]

Answer:

Explanation:

Height covered = 12m

time to fall by 12 m

s = 1/2 gt²

12 = 1/2 g t²

t = 1.565 s

Horizontal distance of throw

= 8.5 x 1.565

= 13.3 m

This distance is to be covered by dog during the time ball falls ie 1.565 s

Speed of dog required = 13.3 / 1.565

= 8.5 m /s

b ) dog will catch the ball at a distance of 13.3 m .

4 0

3 years ago

How can you tell animal and plant cells apart

Lynna [10]

Well there are a couple ways. 1: The easiest, plant cells have a cell wall or extra protection. You will not find this on an animal cell, as there is only a membrane. 2: Chloroplast. This also will not be found in animal cells as they produce the plant's green color as well as the sugar. Hope this helps!

8 0

3 years ago

An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time

umka21 [38]

Answer:

Explanation:

s = s₀ + v₀t + ½at²

s = 0 + 0(15) + ½(6)(15²)

s = 675 m

Not sure what the free fall acceleration is needed for, but if the object is dropped from a high enough point, it will travel in 15 seconds

s = ½10(15²) = 2250 m if air resistance is ignored

7 0

2 years ago