What is the gravitational force between two identical 5000 kg asteroids whose centers of mass are seperated by 100 m?

1 answer:

7 0

For this question we use the Newtonian relationship F = GMm/r^2.

We often use this relationship when describing one small object orbiting a much more massive one, such as the moon orbiting the Earth. In that case it is obvious that the Earth's mass is M, and the moon's mass is m. In reality it isn't extremely important anyway, but in the case of two identical masses we would ignore the convention.

So, where G is the universal gravitational constant, M = m = 5000kg, and r is the distance between the centres of mass of the two asteroids (100m):

F = GMm/r^2 = (6.67*10^-11)(5000)(5000)/(100^2) = 1.67*10^-7 N.

This answer is to three significant figures. I hope this helps you :)

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How much force is required to accelerate a .6 kg object at 5 m/s^2

vodomira [7]

Answer:

$.$

» 30 N

Explanation:

<u>Given</u> :

Mass → m → 6kg

Acceleration → a →

$5 {ms}^{ - 2}$

<u>To</u><u> </u><u>find</u> :

The formula for force

F = m • a

F = 6 • 5

F = 30 N

7 0

2 years ago

In a collision, a 15 kg object moving with a velocity of 3 m/s transfers some of its momentum to a 5 kg object. What would be th

Misha Larkins [42]

The key to solve this problem is the conservation of momentum. The momentum of an object is defined as the product between the mass and the velocity, and it's usually labelled with the letter $p$ :

$p=mv$

The total momentum is the sum of the momentums. The initial situation is the following:

$m_A=15,\quad v_A=3,\quad m_B=5,\quad v_B=0$

(it's not written explicitly, but I assume that the 5-kg object is still at the beginning).

So, at the beginning, the total momentum is

$p=m_Av_A+m_Bv_B=15\cdot 3+5\cdot 0=45$

At the end, we have

$m_A=15,\quad v_A=1,\quad m_B=5,\quad v_B=x$

(the mass obviously don't change, the new velocity of the 15-kg object is 1, and the velocity of the 5-kg object is unkown)

After the impact, the total momentum is

$p=m_Av_A+m_Bv_B=15\cdot 1+5\cdot x=15+5x$

Since the momentum is preserved, the initial and final momentum must be the same. Set an equation between the initial and final momentum and solve it for $x$ , and you'll have the final velocity of the 5-kg object.