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zavuch27 [327]
2 years ago
14

Someone please help:( I will really appreciate it

Mathematics
1 answer:
Len [333]2 years ago
4 0

Answer:

What do u need help with I don't get what u need help with

Step-by-step explanation:

You might be interested in
If b
lys-0071 [83]

Answer:

46.2^o

Step-by-step explanation:

<u><em>The correct question is</em></u>

If b = 9 and c = 13, what is the measure of ∠A? (round to the nearest tenth of a degree)

The picture in the attached figure

we know that

In the right triangle ABC

cos(A)=\frac{b}{c} ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

cos(A)=\frac{9}{13}

using a calculator

A=cos^{-1}(\frac{9}{13})=46.2^o

7 0
3 years ago
Write an equivalent expression by factoring.<br><br>5x + 15​
nata0808 [166]

Answer:

5(x+3)........ ...........

5 0
3 years ago
Two friends are collecting stuffed animals. Veronica has 5 more than double the number of stutted
STatiana [176]

v + m = 32 and v = 5 + 2m are the equations that are used  to determine m, the number of stuffed animals Mariposa has

Number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23

<h3><u>Solution:</u></h3>

Let "v" be the number of stuffed animals with Veronica

Let "m" be the number of stuffed animals with Mariposa

Given that,

Together, they have 32 stuffed animals

Therefore,

v + m = 32  --------- eqn 1

Veronica has 5 more than double the number of stutted  animals as her friend Mariposa

Therefore,

Number of stuffed animals with Veronica = 5 + 2(number of stuffed animals with Mariposa)

v = 5 + 2m ---------- eqn 2

Thus eqn 1 and eqn 2 can be used to determine m, the number of stuffed animals Mariposa has

Let us solve eqn 1 and eqn 2

Substitute eqn 2 in eqn 1

5 + 2m + m = 32

5 + 3m = 32

3m = 32 - 5

3m = 27

<h3>m = 9</h3>

Substitute m = 9 in eqn 2

v = 5 + 2(9)

v = 5 + 18

<h3>v = 23</h3>

Thus number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23

5 0
3 years ago
The average number of accidents is 3 per month, what is the probability of 1 accident?
tatuchka [14]
<h2>Hello!</h2>

The answer is: 33.33%

<h2>Why?</h2>

Since we have the average number of accidents that occurs in 1 month, and it's equal to 3, we can calculate the probability of 1 accident occurs by dividing it into the average number of accidents, using the following formula:

Probability=\frac{FavorableOutcomes}{Outcomes}*100

Where,

Favorable outcomes are the occurrence of the event, for this case, it's equal to 1.

Outcomes are the possible occurrence of the event, for this case, it's equal to 3.

So, by substituting we have:

Probability=\frac{1}{3}*100

Probability=0.3333*100=33.33

So, the probability will be equal to 33.33%

Have a nice day!

7 0
3 years ago
Can anyone help me figure out how to do this
3241004551 [841]

Answer:

133m^2

Step-by-step explanation:

What if i say NO?

jk

3*3=9

8+3=11

12-3=9

sp

9*11=99

2 area coverd so far

99+9=108

7*2=14

108+14=122

Lastly the tir

10-7=3

11-3-2=6

6*4=24

24/2=12

133m^2

8 0
2 years ago
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