Answer:
9.606 grams of citric acid are present in 125 mL of a 0.400 M citric acid solution.
Explanation:
Molarity : It is defined as the number of moles of solute present in one liter of solution. Mathematically written as:

Moles of citric acid = n
Volume of the citric acid solution = 125 mL =125 × 0.001 L= 0.125 L
(1 mL = 0.001L)
Molarity of the citric acid solution = 0.400 M

n = 0.400 M × 0.125 L = 0.05 moles
Mass of 0.05 moles of citric acid :

9.606 grams of citric acid are present in 125 mL of a 0.400 M citric acid solution.
Answer:

Explanation:
The expression for Clausius-Clapeyron Equation is shown below as:
Where,
P is the vapor pressure
ΔHvap is the Enthalpy of Vaporization
R is the gas constant (8.314×10⁻³ kJ /mol K)
c is the constant.
For two situations and phases, the equation becomes:

Given:
= 13.95 torr
= 144.78 torr
= 25°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (25 + 273.15) K = 298.15 K
= 298.15 K
= 75°C = 348.15 K
So,





Yes it was appropriate according to this article”Vinegar and lemon juice are great options if you're looking for a good home remedy for bee stings and wasp stings too. Both contain a type of acid that will help to neutralise the sting and provide a soothing sensation.”
The correct answer I believe is sunlight