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3 years ago

Hey guys!

Chemistry

1 answer:

melamori03 [73]3 years ago

7 0

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You might be interested in

Need help ASAP! How many moles of sodium nitrate are in 0.25 L of 1.2 M NaNO3 solution?

Setler79 [48]

Answer:

$\boxed {\boxed {\sf 0.3 \ mol \ NaNO_3}}$

Explanation:

Molarity is a measure of concentration in moles per liter.

$molarity= \frac{moles \ of \ solute}{liters \ of \ solution}$

The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.

molarity= 1.2 mol NaNO₃/L
liters of solution=0.25 L
moles of solute =x

$1.2 \ mol \ NaNO_3/L= \frac{x}{0.25 \ L}$

We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.

$0.25 \ L *1.2 \ mol \ NaNO_3/L=\frac{x}{0.25 \ L} *0.25 \ L$

$0.25 \ L *1.2 \ mol \ NaNO_3/L=x$

The units of liters cancel, so we are left with the units moles of sodium nitrate.

$0.25 *1.2 \ mol \ NaNO_3=x$

$0.3 \ mol \ NaNO_3=x$

There are 0.3 moles of sodium nitrate.

3 0

3 years ago

What is a chemical treatment process used to remove dissolved ionic species from contaminated aqueous streams?

NeTakaya

Answer:

Ion exchange.

Explanation:

One of the ways in which water can be treated is through the process known as ION EXCHANGE. Using this for treating water has to do basically with the transfer or say the exchange of ions.

Ion exchanges is done by exchanging ions which are considered as 'unfit' or contaminants by the ones that are "fit".

Ions from what is known as zeolite or resin is been exchanged with the ions in the water. Cations are exchanged with cations and anions are exchanged with anions.

NB: this method is a good method or removing contaminants that are ions but not contaminants that are not ions.

6 0

3 years ago

What element has 2 electrons in the 4s sub level?

ruslelena [56]

is the Calcium because the calcium in group two which group two has 2 electron and also calcium and Potassium 4s sub level group potassium has 1 electron. :)

4 0

3 years ago

If 0.500 mol neon at 1.00 atm and 273 K expands against a constant external pressure of 0.100 atm until the gas pressure reaches

trapecia [35]

Answer:

The work done on neon = -323 J

The internal energy change= -392.84 J

The heat absorbed by neon = -69.84 J

Explanation:

Step 1: Data given

Number of moles = 0.500 moles

Pressure = 1 atm

Temperature = 273 Kelvin

The pressure will change from 1.00 atm to 0.200 atm. The temperature changes from 273 to 210 Kelvin.

a) calculate the work done on neon

W = -P(V2-V1)

⇒ with P = the pressure = 0.1 atm

⇒ with V1 = the initial volume = nRTi /Pi

⇒ with V2 = the final volume = nRTf /Pf

W = -PnR((T2/P2) -(T1/P1))

⇒ with T2 = the final temperature = 210 K

⇒ with T1 = the initial temperature = 273 K

⇒ with P2 = the final pressure = 0.200 atm

⇒ with P1 = the initial pressure = 1.00 atm

W = -nR (210*(0.1/0.2) - 273*(0.1/1.00))

W = -nR*(105 - 27.3)

W= -(0.500)*(8.314)*(77.7)

W = -323 J

b) calculate the internal energy change

E = (3/2)*nRT

ΔE = Ef - Ei

ΔE =(3/2)*nR(T2-T1)

⇒ with n= number of moles = 0.500 moles

⇒ with T2 =the final temperature = 210 K

⇒ with T1 = the initial temperature = 273 K

ΔE = (3/2)*(0.5)*(8.314)(210-273)

ΔE = -392.84 J

c) Calculate the heat absorbed by neon

ΔE = q + W

q = ΔE -W

⇒ with ΔE = -392.84 J

⇒ with W = -323 J

q = -392.84 J -( -323 J)

q =-392.84 J + 323 J

q = -69.84 J

4 0

3 years ago

A compound is 44.7% P and the rest O. Determine its emperical formula.

svet-max [94.6K]

Answer:

P₅O₁₂

Explanation:

Assume that you have 100 g of the compound.

Then you have 44.7 g P and 55.3 g O.

1. Calculate the moles of each atom

Moles of P = 44.7 × 1/30.97 = 1.443 mol Al

Moles of O = 55.3 × 1/16.00 = 3.456 mol O

2. Calculate the molar ratios.

P: 1.443/1.443 = 1

O: 3.456/1.443 = 2.395

3. Multiply by a number to make the ratio close to an integer

P: 5 × 1 = 5

O: 5 × 2.395 = 11.97

3. Determine the empirical formula

Round off all numbers to the closest integer.

P: 5

O: 12

The empirical formula is P₅O₁₂.

6 0

3 years ago