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Tanzania [10]
3 years ago
15

What is the shorthand electron configuration for Ba2+​

Chemistry
1 answer:
Arada [10]3 years ago
3 0
Since the barium ion will be isoelectronic to the nearest noble gas, which is xenon, the electronic configuration for Ba2+ is: [Xe]
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What is meant by being a base.<br> What is the meaning of a hydrogen acceptor
kiruha [24]
My answer -

 
hydrogen acceptor any substance ( CYTOCHROME OXIDASE) that can become reduced by the addition of hydrogen, thus enabling the transfer and release of energy as in the ELECTRON TRANSPORT SYSTEM.

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8 0
4 years ago
How many valence electrons are in the electron-dot structures for the elements in group 3a(13)?
frosja888 [35]
Three valence electrons
3 0
3 years ago
What is the purpose of balancing chemical reactions?
Karo-lina-s [1.5K]

Answer: I believe its 1

Hope this helps!

4 0
2 years ago
If the heat of fusion for water is 334 j/g, how many Jules are needed to melt 45.0 g of ice at 0.0°c?
finlep [7]

Given parameters:

Heat of fusion of water  = 334j/g

Mass of ice  = 45g

Temperature of ice =  0.0°c

Unknown:

Amount of heat needed to melt = ?

Solution:

This is simply a phase change and a latent heat is required in this process.

  To solve this problem; use the mathematical expression below;

             H  = mL

where m is the mass

            L is the heat of fusion of water;

              H  = 45 x 334  = 15030J

7 0
4 years ago
Determine the volume of distilled water that should be added to 20.0 mL of 12.0 M HCl(aq) in order to prepare a 0.500 M HCl(aq)
BARSIC [14]

Answer:

V_{H_2O}=460 mL

Explanation:

Hello!

In this case, in a dilution process, water is added to a solute in order to decrease its concentration but increase the volume of the solution. It means that if we have 20.0 mL of a 12.0-M solution of HCl and we want a 0.500-M solution, we need to apply the following formula considering that the moles remain unchanged:

M_1V_1=M_2V_2

Thus, solving for the final volume is:

V_2=\frac{M_1V_1}{M_2}

So plugging in the values we obtain:

V_2=\frac{12.0M*20.0mL}{0.500M}\\\\V_2=480 mL

Now, since the initial volume of acid was 20.0 mL and the final volume is 480 mL, the added volume of distilled water is:

V_{H_2O}=480-20=460 mL

Best regards!

8 0
3 years ago
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