Question

An ant walks 2\,\text m2m2, start text, m, end text to the right and then climbs 1 \,\text m1m1, start text, m, end text up a wall.How many degrees above the ground is the ant compared to its initial position?

Answer 1

Answer:

26.56°

Explanation:

given,

horizontal distance travel by the ant = 2 m

vertical distance travel by the ant = 1 m

angle of the ant above the initial point = ?

using trigonometric function

$tan \theta = \dfrac{h}{x}$

θ is the angle of the ant form initial position

h is the height on the wall

x is the horizontal distance covered by the ant

$tan \theta = \dfrac{1}{2}$

$\theta =tan^{-1}(0.5)$

$\theta =26.56^0$

hence, the angle made by the ant from the initial position is equal to 26.56°