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velikii [3]
3 years ago
11

A golfer tees off and hits a golf ball at a speed of 31 m/s and at an angle of 35 degrees. What is the horizontal velocity compo

nent of the ball? Round the answer to the nearest tenth of a m/s
Physics
2 answers:
Sever21 [200]3 years ago
8 0
The horizontal component of the velocity of the ball is calculated by multiplying the speed by the cosine of the given angle. 
                        x-component of speed = (31 m/s)(cos 35°) 
                                                               = 25.39 m/s
Thus, the horizontal velocity component of the ball is 25.39 m/s. 
lawyer [7]3 years ago
5 0

Answer:

Horizontal component of the speed is given as

v_x = 25.4 m/s

Explanation:

As we know that if a vector is inclined at some angle with the horizontal then the component of the vector along and perpendicular to horizontal is given as

A_x = Acos\theta

A_y = Asin\theta

now here we need to find the component of velocity

so we know that

v = 31 m/s

\theta = 35^0

now we will have

v_x = 31cos35

v_x = 25.4 m/s

so horizontal component of the speed will be 25.4 m/s

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At what distance from the wire is the magnitude of the electric field equal to 2.41 n/cn/c ?
Sladkaya [172]

The correct answer is 1.07m.

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Here, is the charge per unit length, r is the distance from the wire, and

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E= λ/2πε_0r

Rearrange the equation for r.

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At a distance of 1.07 m the magnitude of electric field is 2.41 N/C.

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In Science, the property which helps to explain differences in the specific heat capacities of two substances is the forces between molecules.

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