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velikii [3]
3 years ago
11

A golfer tees off and hits a golf ball at a speed of 31 m/s and at an angle of 35 degrees. What is the horizontal velocity compo

nent of the ball? Round the answer to the nearest tenth of a m/s
Physics
2 answers:
Sever21 [200]3 years ago
8 0
The horizontal component of the velocity of the ball is calculated by multiplying the speed by the cosine of the given angle. 
                        x-component of speed = (31 m/s)(cos 35°) 
                                                               = 25.39 m/s
Thus, the horizontal velocity component of the ball is 25.39 m/s. 
lawyer [7]3 years ago
5 0

Answer:

Horizontal component of the speed is given as

v_x = 25.4 m/s

Explanation:

As we know that if a vector is inclined at some angle with the horizontal then the component of the vector along and perpendicular to horizontal is given as

A_x = Acos\theta

A_y = Asin\theta

now here we need to find the component of velocity

so we know that

v = 31 m/s

\theta = 35^0

now we will have

v_x = 31cos35

v_x = 25.4 m/s

so horizontal component of the speed will be 25.4 m/s

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How to find wavelength
Andrews [41]
If the wavelength<span> is given, the energy can be determined by first using the wave equation (c = λ × ν) to </span>find<span> the frequency, then using Planck's equation to </span>calculate<span> energy. Use the equations above to answer the following questions. 1. Ultraviolet radiation has a frequency of 6.8 × 1015 1/s.</span>
4 0
3 years ago
1. What are the units of : pressure, force , area
White raven [17]

Pressure- Pascal(N/m^2)

Force- Newton

Area-m^2(Square metre)

<u>Explanation:</u>

  • Pressure is force continuous force applied to an object. The applied force is always perpendicular to the surface of the object.
  • Force is a push or pulls on an object by an external body where it changes its state from rest to motion.
  • Force is said to have both magnitude and direction.
  • Area is the portion that shows the scale of a 2D form or configuration in the level. The covering area is its analog on the 2D surface of a 3D object.
6 0
3 years ago
When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The mass is now displ
Ray Of Light [21]

Answer:

period of oscillations is 0.695 second

Explanation:

given data

mass m = 0.350 kg

spring stretches x = 12 cm = 0.12 m

to find out

period of oscillations

solution

we know here that force

force = k × x   .........1

so force = mg =  0.35 (9.8)  = 3.43 N

3.43 = k × 0.12

k = 28.58 N/m

so period of oscillations is

period of oscillations = 2π × \sqrt{\frac{m}{k} }   ................2

put here value

period of oscillations = 2π × \sqrt{\frac{0.35}{28.58} }  

period of oscillations = 0.6953

so period of oscillations is 0.695 second

4 0
3 years ago
The four tires of an automobile are inflated to a gauge pressure of 2.2 105 Pa. Each tire has an area of 0.023 m2 in contact wit
Stels [109]

Answer:

Force, F = 20240 N

Explanation:

It is given that,

Pressure exerted by the four tires of an automobile, P=2.2\times 10^5\ Pa

Area of each tire, A=0.023\ m^2

Area of 4 tires,  A=0.092\ m^2

We know that the pressure exerted by an object is equal to the force per unit area. Its formula is given by :

P=\dfrac{F}{A}

F=P\times A

F=2.2\times 10^5\times 0.092

F = 20240 N

So, the weight of the automobile is 20240 N. Hence, this is the required solution.

7 0
3 years ago
A small sphere with a mass of 441 g is moving upward along the vertical +y-axis when it encounters an electric field of 5.00 N/C
sweet-ann [11.9K]
In your question where the ask is to calculate the charge that the small sphere carries which is the mass of it is 441g moving at an acceleration of 13m/s^2 nad having and electric field of 5N/C. So the formula in getting the charge is mutliply the mass and the quotients of Acceleration and the Electric Field so the answer is 1,146.6
3 0
3 years ago
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