Answer:
a) x = ⅔ d
, b) the charge must be negative, c) Q
Explanation:
a) In this exercise the force is electric between the charges, we are asked that the system of the three charges is in equilibrium, we use Newton's second law. Balance is on the third load that we are placing
∑ F = 0
-F₁₂ + F₂₃ = 0
F₁₂ = F₂₃
let's replace the values
k Q Q / r₁₂² = k Q 4Q / r₂₃²
Q² / r₁₂² = 4 Q² / r₂₃²
suppose charge 3 is placed at point x
r₁₂ = x
r₂₃ = d-x
we substitute
1 / x² = 4 / (d-x) 2
1 / x = 2 / (d-x)
x = 2 (x-d)
x = 2x -2d
3x = 2d
x = ⅔ d
b) The sign of the charge must be negative, to have an attractive charge on the two initial charges
c) Q
Answer:
P = 15.90 W
Explanation:
given,
speed of conveyor belt = 0.56 m/s
conveyor belt move up to = 2 m
angle made with the horizontal = 15°
mass of the box = 2.1 kg
rate is the force of the conveyor belt doing work on the box as the box moves up
P = F v cos ∅
P = 3 × 9.8 × 0.56 × cos 15°
P = 15.90 W
Explanation:
Newton's second law of motion is F = ma, or force is equal to mass times acceleration
