Answer:
Distance of the point where electric filed is 2.45 N/C is 1.06 m
Explanation:
We have given charge per unit length, that is liner charge density 
Electric field E = 2.45 N/C
We have to find the distance at which electric field is 2.45 N/C
We know that electric field due to linear charge is equal to
, here 
is linear charge density and r is distance of the point where we have to find the electric field
So 
r = 1.06 m
So distance of the point where electric filed is 2.45 N/C is 1.06 m
Answer:
"1155 N" is the appropriate solution.
Explanation:
Given:
Acceleration,
Forces resisting motion,
Mass,
By using Newton's second law, we get
⇒ 
Or,
⇒ 
By putting the values, we get
⇒ 
⇒ 
⇒ 
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hope this helps!<span />
short wavelengths and high frequencies. long wavelengths and low frequencies. high frequencies and long wavelength. 0 of 2
