The Vagus nerve is one of 12 nerves. It is the longest of the cranial nerves, extending from the brainstem to the abdomen by way of multiple organs including the heart, esophagus, and lungs it is also known as cranial nerve X.
Answer:
<h2>
E = 2.8028*10⁻¹⁹ Joules</h2>
Explanation:
The minimum energy needed to eject electrons from a metal with a threshold frequency fo is expressed as E = hfo
h = planck's constant
fo = threshold frequency
Given the threshold frequency fo = 4.23×10¹⁴ s⁻¹
h = 6.626× 10⁻³⁴ m² kg / s
Substituting this value into the formula to get the energy E
E = 4.23×10¹⁴ * 6.626 × 10⁻³⁴
E = 28.028*10¹⁴⁻³⁴
E = 28.028*10⁻²⁰
E = 2.8028*10⁻¹⁹ Joules
Answer:
<u><em>The plank moves 0.2m from it's original position</em></u>
Explanation:
we can do this question from the constraints that ,
- the wheel and the axle have the same angular speed or velocity
- the speed of the plank is equal to the speed of the axle at the topmost point .
thus ,
<em>since the wheel is pure rolling or not slipping,</em>
<em>⇒</em>
where
<em> - speed of the wheel</em>
<em> - angular speed of the wheel</em>
<em> - radius of the wheel</em>
<em>since the wheel traverses 1 m let's say in time '' ,</em>
<em></em>
∴
⇒
the speed at the topmost point of the axle is :
⇒
this is the speed of the plank too.
thus the distance covered by plank in time '' is ,
⇒
For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as
E1=1.598*10^11v/m
<h3>What is the e
lectric field intensity 20cm away from the
rod along its perpendicular
bisector?</h3>
Generally, the equation for the initial electric field intensity is mathematically given as
Therefore
Hence
E1=B*9*10^{13})/(10*110)*
E1=1.598*10^11v/m
In conclusion, the electric field intensity
E1=1.598*10^11v/m
Read more about Electric field
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