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GalinKa [24]
3 years ago
14

7. Plasma from blood (density = 1025 kg/m3) flows along a vertical channel in a steady, incompressible, fully developed laminar

film of thickness h. (i) Simplify the continuity and Navier-Stokes equations to model this flow field. (ii) Obtain expressions for the velocity profile, (iii) the shear stress distribution, (iv) the volume flow rate, and (v) the average velocity. (vi) Relate the plasma film thickness to the volume flow rate per unit depth of surface normal to the flow. (vii) Calculate the volume flow rate for h = 0.5 mm, flowing down a surface b = 2 cm wide.

Physics
1 answer:
Goryan [66]3 years ago
6 0

Answer: Q = 8.37×10^-9L/s

Explanation: since the depth of the surface is normal to the flow, ø = 90

Find the attached file for the solution

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In serving, a tennis player accelerates a 59 g tennis ball horizontally from rest to a speed of 34 m/s Assuming that the acceler
Akimi4 [234]

Answer:

The magnitude of the force exerted on the ball by the racquet is 94.73 N.

Explanation:

The force exerted on the ball is the following:

F = ma

Where:

m: is the mass of the ball = 59 g

a: is the acceleration

The acceleration of the ball can be found with the following kinematic equation:

v_{f}^{2} = v_{0}^{2} + 2ad

Where:

d: is the distance = 0.36 m

v_{f}: is the final speed = 34 m/s

v_{0}: is the initial speed = 0 (it start from rest)

Hence, the acceleration is:

a = \frac{v_{f}^{2}}{2d} = \frac{(34 m/s)^{2}}{2*0.36 m} = 1605.6 m/s^{2

Finally, the force is:

F = ma = 59 \cdot 10^{-3} kg*1605.6 m/s^{2} = 94.73 N    

Therefore, the magnitude of the force exerted on the ball by the racquet is 94.73 N.                                

                                                                 

I hope it helps you!                                                              

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3 years ago
You are holding a block of wood with dimensions 3 cm x 6 cm x 9 cm on the
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3 years ago
A marble rolls off a table with a speed of 2.30 m/s. If the table is 1.12 m high, how far from the
Vlada [557]

Answer:

1.10 m

Explanation:

First, find the time it takes to land.

Given, in the y direction:

Δy = 1.12 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(1.12 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 0.478 s

Next, find the distance traveled in that time.

Given, in the x direction:

v₀ = 2.30 m/s

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Find: Δx

Δx = v₀ t + ½ at²

Δx = (2.30 m/s) (0.478 s) + ½ (0 m/s²) (0.478 s)²

Δx = 1.10 m

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4 years ago
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