Question

Nicole throws a ball straight up. Chad watches the ball from a window 6.10m above the point where Nicole released it. The ball passes Chad on the way up, and it has a speed of 12.0m/s as it passes him on the way back down.How fast did Nicole throw the ball?

Answer 1

Answer:

$v=16.234m/s$

Explanation:

Given data

Distance S=6.10 m

Initial Speed u=12.0 m/s

To find

Final Speed v

Solution

From third equation of motion we know that:

$v^{2}-u^{2}=2aS$

where

v is final velocity

u is initial velocity

a is acceleration

S is distance

Substitute the given values to find v

$v^{2}=u^{2}+2aS\\v^{2}=(12.0m/s)^{2} +2(9.8m/s^{2} )(6.10m)\\v^{2}=263.56\\ v=\sqrt{263.56}\\ v=16.234m/s$