Once the cake is removed from the oven, it has been exposed to the room temperature of 70°F. After 10 minutes, the cake's temperature decreased to 200°F, which is 150°F cooler than it initially was (350°F). As for the what is asked, 90°F is 260°F cooler than its original temperature (350°F).
This problem can be expressed in a ratio:
10mins:150<span>°F = N:260</span><span>°F
where N is how long it will take for</span><span> cake to cool to 90°F
</span>150<span>°FxN=10x260
</span>150N=2600
N=2600/150
N=17.33
N<span>≈20 minutes
Thus, it takes approximately 20 minutes </span><span>for the cake to cool to 90°F</span>
Answer:
Work individually or in teams of two to construct and launch paper rockets using a teacher-built PVC-pipe launcher.
Following the flight of their rocket, calculate the altitude their rocket achieved.
Based on the flight performance of their rockets, analyze their rocket designs, modify or rebuild them, launch again, and calculate the altitude achieved to determine if their changes affected the performance of the rocket.
Conclude the activity by writing a post-flight mission report.
Materials
Answer:
1/6
Step-by-step explanation:
Let x represent the proportion of time the third person spends on the project. You want ...
1/2 + 1/3 + x = 1 . . . . full-time equivalents
5/6 + x = 1 . . . . simplify
x = 1/6 . . . . . . . subtract 5/6
The third person should budget 1/6 of their time to the project.
Answer:
i believe the answer is c
Step-by-step explanation:
tbh i dont have to explain cause you mainly have to just look at the graph
You can use the quadratic equation to solve this once you have this set equal to zero. The answers would be roughly 9.6 and -0.6.
