I hope this helps you
-2a^2b.4.a^5.b^2
-8.(a^2+5)(b^1+2)
-8.a^7.b^3
Answer:
Step-by-step explanation:
V=πr2h
3
r Radius
h Height
Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
Answer:
take angle U as reference angle
using sine rule
sin U=opposite/hypotenuse
sinU=42/42
sin U=1
sin 90=1
therefore the value of U is 90 degree
Step-by-step explanation:
Answer:
yesss it makes sense!!!!!!!!!!!