Answer:
Correct
Correct
Incorrect
Step-by-step explanation:
1) y-intercept => x = 0, => y = f(0) = 0 - 0 + 0 - 36 = -36
2) x-intercept => y = 0 => factor the function (start by dividing by x -2)
f(x) = (x-2)(x-3)(x-6) =0 => x =2, x = 3, x = 6 (these are the x-intercepts)
3) critical points:
between x = 2 and x = 3, there is a local maximum
between x =3 and x = 6 there is a local minimum
3) Shape.
The function comes growing from - infinity.
In the third quadrant the function is negative (it does not pass throuhg the second quadrant)
It enters to the fourth quadrant intercepting the y-axis at y = -36. It continues growing and intercepts the x-axis at x = 2.
It continues increasing until a maximum local positive value, starts to decrease, intercepts the x-axis at x = 3, continues decreasing, becomes negative, gets a local minimum in the fourth quadrant, starts to increase, intercepts the x-axis at x = 6, becomes positive, and continues growing.
Answer:
Never
Step-by-step explanation:
It is not possible for one out of two parallel lines to be cut by a transversal, because eventually it would have to intersect
Pretty sure the answer is 3t26tr <3
Step-by-step explanation: need to find a basis for the solutions to the equation Ax = 0. To do this ... 0 0 0 1 −3. ⎤. ⎦. From this we can read the general solution, x = ⎡. ⎢. ⎢. ⎢. ⎢. ⎣ ... two vectors are clearly not multiples of one another, they also give a basis. So a basis ... 4.4.14 The set B = {1 − t2,t − t2,2 − 2t + t2} is a basis for P2.
