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1. 10.0 grams of water in the form of a solid has a temperature of 0.0 °C. This cube of

Ainat [17]

The initial 10.0 grams of water is a kind of intensive property.

What do you mean by intensive properties?

Intensive properties are those properties which do not depend upon the amount of the given substance. For example Temperature and pressure.

Generally, grams are used to represent concentrations. Therefore, always consider extensive. However, in the given question, the concentration is specified i.e. means fixed. So, the 10.0 grams of water become intensive in the given conditions.

Hence, the answer is an intensive property.

To learn more about the intensive property concept Check the given link

brainly.com/question/1496355

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4 0

1 year ago

Chloral hydrate (C2H3Cl3O2) is a drug formerly used as a sedative and hypnotic.

Dmitrij [34]

Answer :

(a) The molar mass of $C_2H_3Cl_3O_2$ is, 165.5 g/mole

(b) The moles of $C_2H_3Cl_3O_2$ is, 3.02 moles

(c) The mass in grams of $2.0\times 10^{-2}$ mole chloral hydrate is, 3.31 g

(d) The number of chlorine atoms in 5.0 g chloral hydrate is, $5.4\times 10^{22}$

(e) The mass of chloral hydrate will be, 1.55 g

(f) The mass of exactly 500 molecules of chloral hydrate is, $1.99\times 10^{23}$

Explanation :

(a) To calculate the molar mass of chloral hydrate.

The formula of chloral hydrate is, $C_2H_3Cl_3O_2$

Atomic mass of carbon = 12 g/mole

Atomic mass of hydrogen = 1 g/mole

Atomic mass of oxygen = 16 g/mole

Atomic mass of chlorine = 35.5 g/mole

Now we have to determine the molar mass of chloral hydrate.

$\text{Molar mass of }C_2H_3Cl_3O_2$ =2(12g/mole)+3(1g/mole)+3(35.5g/mole)+2(16g/mole)=165.5g/mole[/tex]

The molar mass of $C_2H_3Cl_3O_2$ is, 165.5 g/mole

(b) Now we have to determine the moles of $C_2H_3Cl_3O_2$ .

$\text{Moles of }C_2H_3Cl_3O_2=\frac{\text{Mass of }C_2H_3Cl_3O_2}{\text{Molar mass of }C_2H_3Cl_3O_2}=\frac{500.0g}{165.5g/mole}=3.02moles$

The moles of $C_2H_3Cl_3O_2$ is, 3.02 moles

(c) Now we have to determine the mass in grams of $2.0\times 10^{-2}$ mole chloral hydrate.

$\text{Mass of }C_2H_3Cl_3O_2=\text{Moles of }C_2H_3Cl_3O_2\times \text{Molar mass of }C_2H_3Cl_3O_2$

$\text{Mass of }C_2H_3Cl_3O_2=(2.0\times 10^{-2}mole)\times (165.5g/mole)=3.31g$

The mass in grams of $2.0\times 10^{-2}$ mole chloral hydrate is, 3.31 g

(d) To calculate the number of chlorine atoms are in 5.0 g chloral hydrate.

First we have to determine the moles of $C_2H_3Cl_3O_2$ .

$\text{Moles of }C_2H_3Cl_3O_2=\frac{\text{Mass of }C_2H_3Cl_3O_2}{\text{Molar mass of }C_2H_3Cl_3O_2}=\frac{5g}{165.5g/mole}=0.03moles$

Now we have to calculate the number of chlorine atoms in chloral hydrate.

In $C_2H_3Cl_3O_2$ , there are, 2 carbon atoms, 3 hydrogen atoms, 3 chlorine atoms and 2 oxygen atoms.

As, 1 mole of $C_2H_3Cl_3O_2$ contains $3\times 6.022\times 10^{23}$ chlorine atoms

So, 0.03 mole of $C_2H_3Cl_3O_2$ contains $0.03\times 3\times 6.022\times 10^{23}=5.4\times 10^{22}$ chlorine atoms

The number of chlorine atoms in 5.0 g chloral hydrate is, $5.4\times 10^{22}$

(e) To calculate the mass of chloral hydrate would contain 1.0 g Cl.

As, $3\times 35.5g$ of chlorine present in 165.5 g of $C_2H_3Cl_3O_2$

So, 1 g of chlorine present in $\frac{165.5}{3\times 35.5}=1.55g$ of $C_2H_3Cl_3O_2$

The mass of chloral hydrate will be, 1.55 g

(f) To calculate the mass of exactly 500 molecules of chloral hydrate.

As, $6.022\times 10^{23}$ molecules of chloral hydrate has 165.5 g mass of chloral hydrate

So, 500 molecules of chloral hydrate has $\frac{6.022\times 10^{23}}{500}\times 165.5=1.99\times 10^{23}$ mass of chloral hydrate

The mass of exactly 500 molecules of chloral hydrate is, $1.99\times 10^{23}$

3 0

3 years ago

Based on formal charges, draw the most preferred Lewis structure for the chlorate ion, ClO3−. To add lone pairs, click the butto

vova2212 [387]

Answer:

The structure is shown in the diagram.

Explanation:

Lewis structure : In order to draw Lewis structure we will calculate the total number of valence electrons in the molecule.

The valence electrons from Cl : 7

The valence electrons from O = 3 X 6 = 18

Charge negative so more electrons = 2

total electrons = 7 + 18 +2 = 27

Now we will distribute the electrons on each atom and in between atoms as shown in the diagram.

8 0

3 years ago

Read 2 more answers

Determine the mass of chloride (MW = 35.45 g/mol ) in grams present in 100 mL of a 0.273 M solution of aqueous FeCl₃ (iron(III)

Naily [24]

Answer:

The mass chloride is 2.903 grams

Explanation:

Step1: calculate the moles of FeCl3

moles = molarity x volume in liters

volume in liters = 100 ml /1000 = 0.1 L

molarity = 0.273 M = 0.273 mol / L

moles = 0.273 mol /L x 0.1 L = 0.0273 moles

step 2: find the moles of Cl

since there is 3 atoms of cl in FeCl3

= 3 x 0.0273 =0.0819 moles

Step 3: calculate mass of cl

mass= moles x molar mass

=0.0819 moles x 35.45 g/mol = 2.903 g

7 0

3 years ago

Hii pls help me to balance the equation and state the symbols thanksss

velikii [3]

Answer:

I DID HOW I KNOW . I HOPE IT WILL HELP YOU :D

8 0

3 years ago

Which is better disney plus or hulu​

Which is better disney plus or hulu