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Olin [163]
3 years ago
11

Which of these compounds are oxidizing agents?

Chemistry
2 answers:
gtnhenbr [62]3 years ago
8 0

oxidation is process where they give out the electrons

hence the elements with their lower oxidation state are the only possibilities

Ti(III)---- > Ti(IV) + 1e


elena55 [62]3 years ago
6 0

i guess its e) Mn (VII)

if it was wrong pls let me knw


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REALLY NEED HELP!!! Chemistry
kicyunya [14]

Answer:

C.) 2

Explanation:

The pH equation is:

pH = -log[H⁺]

In this equation, [H⁺] is the molarity of the acid. In this case, the acid is HCl. Molarity can be found using the equation:

Molarity (M) = moles / volume (L)

Since you were given moles and volume, you can find the molarity of HCl.

Molarity = moles / volume

Molarity = 0.01 moles / 1.00 L

Molarity = 0.01 M

Now, you can plug the molarity of the acid into the pH equation.

pH = -log[H⁺]

pH = -log[0.01]

pH = 2

3 0
2 years ago
If a sodium ion has 11 protons, 12 neutrons, and 11 electrons, what is the atomic mass of the atom?
iragen [17]

Answer:

23

Explanation:

we do not care about electrons, so 11 + 12 = 23

7 0
3 years ago
Elements that belong to the same period/row!!
-BARSIC- [3]

Answer:

Each row is called a period. Each column is called a group or family.

Explanation:

7 0
3 years ago
A 125g sample of a mixture of salt and sand contains 12% salt.
natka813 [3]
12 % salt is present in 125 g mixture of salt and sand.
Keep in mind that the total percentage is always 100 %
Therefore, if 12 % is the salt, remaining 88 % must be
sand.
a. The amount of mixture is 125 q. Here, 12 % of 125 is
12 * 125 / 100 = 15 g of salt is present in 125 g mixture.
b. The amount of sand can be calculated similarly, 88 %
of 125 g is 88 * 125 / 100 = 110 g of sand is present in
125 g mixture.
4 0
3 years ago
Please Help! I just started balancing equations and my teacher gave me this. Thanks in advance! :D
Alenkasestr [34]
So you need to put numbers before each compound to make sure there are the exact same number of elements on each side. If you put a 4 before NH4 there are 4 Nitrogen and now 16 hydrogen. I just played around with numbers and guessed until I got them even.
8 0
3 years ago
Read 2 more answers
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