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2 years ago

9

Grayson goes to BestBuy to buy a computer for $499, a mouse for $19.99, and a cable cord for $8.99. Grayson buys this on credit

and will pay off the amount of money over 12 equal month payments. How much will Grayson pay each month?

1 answer:

Dennis_Churaev [7]2 years ago

6 0

Answer:

$44

Step-by-step explanation:

499 + 19.99 + 8.99 = 527.98

527.98/12 = 43.9983333 or $44.00

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Evaluate 4(x - 3) + 5x - x^2 for x = 3 <br>A. 2 <br>B. -6 <br>C. 6<br>D. -2

ipn [44]

Answer:

C) x=6...

Step-by-step explanation:

hope this helps...

3 0

2 years ago

Given a function described as equation y =3x+4 ,what is y when x is 1,2,3

belka [17]

Answer:

When x =1, y = 3(1) + 4 = 7

When x = 2, y = 3(2) + 4 = 10

When x = 3, y = 3(3) + 4 = 13

5 0

2 years ago

Can someone help me asap?????

KATRIN_1 [288]

The answer is 175.45

Surface area of a cone = πrs + πr2
Volume of a cone = 1/3πr2h.
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Answers for volume problems should always be in cubic units.

6 0

3 years ago

You are scheduled to work 34 hours per week at your new job, where you earn $13.1 per

Lyrx [107]

13.1 an hour, 34 hours a week
13.1 x 34 = 445.4 a week
to find out how many weeks, divide 4300 and 445.4 which is 9.65 weeks, which is technically 10 weeks

it would take 10 weeks to earn 4300

6 0

1 year ago

The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a

liubo4ka [24]

Answer:

$(x,y,z)=(1477, 1464, 1437)$

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>

Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
Mr.A earns Rs6000

So, the equation would be

$3x + 5y - 4z = 6000$

<h3>Case-2:</h3>

Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
Mr B neither lose nor gain meaning he has made 0₹

hence,

$2x - 3y + z = 0$

<h3>Case-3:</h3>

Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
Mr.C earns 13000₹

therefore,

$- x + 4y + 6z = 13000$

Thus our system of equations is

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\end{cases}\\\begin{cases}2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

Now solve the equation accordingly:

$\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}$

Solving the equation for x and y yields:

$\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}$

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

$\implies z= \dfrac{217000}{151}$

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

6 0

2 years ago