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3 years ago

What is the hybridization of C2H2Cl2

Chemistry

1 answer:

Airida [17]3 years ago

5 0

The shape of C2H2Cl2 is tetrahedral. Tetrahedral molecule is only non-polar when 4 bonding atoms are identical.

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How many iron atoms are there in 2.50moles of each of the following? FeWO4?

RideAnS [48]

2.50 moles (55.85gramsof Fe/ 1 mole) (6.02 x 10^23 atoms / 1) = 8.41 x 10^25 because there is only one Iron present in the compund.

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3 years ago

Where does the energy come from that is needed for an endothermic reaction

4vir4ik [10]

Where else but from the surroundings?

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3 years ago

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Lostsunrise [7]

Time because even if time changes potential and kinetic energy won’t be affected as much

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4 years ago

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Is the following equation balanced? FeCl₃ + MgO → Fe₂O₃ + MgCl₂ A. Yes B. No

VARVARA [1.3K]

Answer:

The answer is B) No.

Explanation:

The equation balanced is:

2 FeCl₃ + 3 MgO → Fe₂O₃ + 3 MgCl₂

Equation balancing can be done by "trial and error" or by algebraic method.

In this way the equation is balanced on both sides having:

2 atoms of Fe, 6 of Cl, 3 of Mg and 3 of 0.

4 0

4 years ago

Consider the two reduction half-reactions: Na+(aq) + e− LaTeX: \longrightarrow⟶ Na(s) Eo = −2.71 V Cl2(g) + 2 e− LaTeX: \longrig

Juli2301 [7.4K]

Answer:

(i) Δ $E^{o}_{cell} }$ = -4.07v

(ii)Δ $G^{o}_{rxn}$ = +785.510 KJ

(iii) The reaction is for an electrolytic cell

Explanation:

In this question, we are tasked with calculating Δ $E^{o}$ and Δ $G^{o}_{rxn}$ for the reaction and determine if the reaction is for a voltaic or electrolytic cell.

We proceed as follows;

Firstly, we write the complete equation of reaction as shown below;

$2Na^{+}$ + $2Cl^{-}$ → $2Na_{(s)}$ + $Cl_{2(g)}$

We can see that chlorine goes from a negative state to zero state. This is indicative of loss of electron which is defined as oxidation

We can also see that sodium went from a positive state to zero state which is indicative of electron gain which is defined as reduction

Mathematically, the value of Δ $E^{o}_{cell} }$ for the reaction can be calculated using the formula below;

Δ $E^{o}_{cell} }$ = Δ $E^{o}_{reduction} }$ - Δ $E^{o}_{oxidation} }$ = -2.71v - 1.36v = -4.07V

The value of Δ $G^{o}_{rxn}$ can be calculated as follows;

Δ $G^{o}_{rxn}$ = -nFΔ $E^{o}_{cell} }$

Where n = 2 and F is 96,500C . We plug these values to get;

Δ $G^{o}_{rxn}$ = -2 × 96,500C× -4.07V = 785,510J = 785.510KJ (1KJ = 1000J)

Now, we answer if this reaction is for a voltaic or an electrolytic cell;

It is for an electrolytic cell because electrons flow from cathode to anode as indicated by magnitude of the Δ $G^{o}_{rxn}$ (positive in value)

7 0

3 years ago