First question is 1:2
Second question is 12
Given:
A fair die is rolled.
It pays off $10 for 6, $7 for a 5, $4 for a 4 and no payoff otherwise.
To find:
The expected winning for this game.
Solution:
If a die is rolled then the possible outcomes are 1, 2, 3, 4, 5, 6.
The probability of getting a 6 is:

The probability of getting a 5 is:

The probability of getting a 4 is:

The probability of getting other numbers (1,2,3) is:


We need to find the sum of product of payoff and their corresponding probabilities to find the expected winning for this game.
Therefore, the expected winnings for this game are $3.50.
The product of 8 and 54 is 46
Answer:
Between 6 and 7
Step-by-step explanation:
6^2 = 6 × 6 = 36
7^2 = 7 × 7 = 49
45 is between 36 and 49
-7y-4x=17y-2x=53
-4x=24y-2x=53
-2x=24y=53
24y+2x=53
You would have to solve one at a time.
y=53/24
y=2.21
x=53/2
x=26.5