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3 years ago

What is the length of the hypotenuse of the triangle when x = 11?

Mathematics

1 answer:

Anastasy [175]3 years ago

8 0

Answer:

6(11)+4=70

5(11)=55

70²+55²

=7259

square root if 7259=85.20

and that's your answer

Goodnight

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The graph shown is the graph of which function?

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Two students, Carlos and Sophie, factored the trinomial -4x2 − 10x + 6. Sophie factored it as -2(2x − 1)(x + 3) and Carlos facto

damaskus [11]

Sophie has factored the term completely while Carlos has not factored the term completely.

Step-by-step explanation:

We need to factor the trinomial:

$-4x^2-10x + 6$

Factoring:

$-4x^2-10x + 6\\Taking\,\,-2\,\,common:\\-2(2x^2+5x-3)\\Now\,\,factoring:\\-2(2x^2+6x-x-3)\\-2(2x(x+3)-1(x+3))\\-2(2x-1)(x+3)$

So, the factored form of $-4x^2-10x + 6$ is $-2(2x-1)(x+3)$

So, Sophie has factored the term completely. The terms are factored when we cannot further simplify it. Since Carlos factored (x+3)(-4x+2) 2 can be taken common from the term (-4x+2) so, it is not factored completely.

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3 years ago

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Answer:

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Step-by-step explanation:

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Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-

Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

$\sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

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