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True [87]
3 years ago
15

An ___________________ states a position on a topic and then supports that position with reasons and evidence.

Chemistry
1 answer:
Yakvenalex [24]3 years ago
3 0
Argument would make the most sense
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According to the conveyor belt mode of ocean circulation, what happens when water reaches the poles
Andrej [43]

Answer: Some salt is trapped between ice crystals, but most are left behind in the unfrozen seawater.

Explanation:

4 0
3 years ago
Read 2 more answers
2.0g divided by 34.0 g times 100% equals what?
Lubov Fominskaja [6]

Answer: \frac{1}{17}

Explanation: \frac{2}{34}\cdot \:100\%\:=\frac{1}{17}

I tried my best, I hope this helps!

7 0
3 years ago
the diagram below represents two beakers, each containing an ice cube and clear liquid. in beaker A the ice cube floats, and in
Mama L [17]

Answer:

The density of the liquid in beaker B is less than the that of ice.

Explanation:

Ice will float if its mass is less than the mass of the liquid it displaces.

For example, the density of ice is less than that of water.

A 10 cm³ cube of ice has a mass of about 9 g, while the mass of 10 cm³ of water is 10 g. Thus, 9 g of ice displaces 10 g of water.

The denser water displaces the lighter ice and the ice floats to the top.

If the density of the liquid is <em>less than</em> that of water, say, 8 g/cm³, the ice will displace only 8 g of the liquid. The ice will sink.

4 0
3 years ago
¿Cuál es el % m/m de una disolución en que hay disueltos 22 g de soluto en 44 g de disolvente?
Archy [21]

The question is as follows: What is the% m / m of a solution in which 22 g of solute are dissolved in 44 g of solvent?

Answer: The% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.

Explanation:

Given: Mass of solute = 22 g

Mass of solvent = 44 g

The percentage m/m is calculated using the following formula.

Mass percentage = \frac{mass of solute}{mass of solvent} \times 100

Substitute the values into above formula as follows.

Mass percentage = \frac{mass of solute}{mass of solvent} \times 100\\= \frac{22 g}{44 g} \times 100\\= 50 percent

Thus, we can conclude that the% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.

5 0
3 years ago
How many moles of oxygen are required to produce 37.15 g CO2? 37.15 g CO2 = mol O2
NNADVOKAT [17]

Answer:

0.84 moles of oxygen are required.

Explanation:

Given data:

Mass of CO₂ produced = 37.15 g

Number of moles of oxygen = ?

Solution:

Chemical equation:

C + O₂     →     CO₂

Number of moles of  CO₂:

Number of moles = mass/molar mass

Number of moles = 37.15 g/ 44 g/mol

Number of moles = 0.84 mol

Now we will compare the moles of oxygen and carbon dioxide.

                          CO₂         :       O₂  

                              1           :         1

                            0.84       :       0.84

0.84 moles of oxygen are required.

6 0
3 years ago
Read 2 more answers
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