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madam [21]
2 years ago
15

How many liters is 1.9 mol of Cl2 at STP?

Chemistry
1 answer:
Lena [83]2 years ago
8 0

Answer:

V = 42.6 L

Explanation:

Given data:

Number of moles of Cl₂ = 1.9 mol

Temperature and pressure = standard

Volume occupy = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm ×  V = 1.9 mol ×0.0821 atm.L /mol.K × 273.15 k

V = 42.6  atm.L / 1 atm

V = 42.6 L

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Decide whether the compound is ionic or molecular, if you can.
mestny [16]

Answer:

Molecular solid

Explanation:

A molecular solid has a low melting point, they are soft and do not conduct electricity.

We have been told in the question that the solid does not really dissolve in water and it's solution does not improve the electrical conductivity of water. Hence, it must be a molecular solid.

7 0
2 years ago
The average adult male has a total blood volume of 5.0 L. After drinking a few beers, he has a BAC of 0.10. What mass of alcohol
stellarik [79]
  B A C ( Blood Alcohol Content ) of 0.10 means that there are 0.10 g of alcohol for every  dl  of blood.
  5 L = 50 dl
  50 * 0.10 g = 5 g
  In his blood is circulating 5 grams of alcohol. 
7 0
3 years ago
Read 2 more answers
On a cool morning (12"C), a balloon is filled with 1.5 L of helium. By mid afternoon, the temperature has soared to 32°C. What i
ddd [48]

Answer:

1.6 L

Explanation:

Using Charle's law  

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = 1.5 L

V₂ = ?

T₁ = 12 °C

T₂ = 32 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (12 + 273.15) K = 285.15 K  

T₂ = (32 + 273.15) K = 305.15 K  

Using above equation as:

\frac{1.5}{285.15}=\frac{V_2}{305.15}

V_2=\frac{1.5\cdot \:305.15}{285.15}

New volume = 1.6 L

8 0
3 years ago
What is the empirical formula for a compound that has 57.5%
Rainbow [258]

Answer:

c

Explanation:

use %composition given to calculate emperical 4mular

8 0
3 years ago
Nuclear decay<br>27Al + He 》 39P<br>​
dybincka [34]

Answer:

_{13}^{27}\text{Al} + \rm _{2}^{4}\text{He} \longrightarrow \, _{15}^{31}\text{P}

Explanation:

The unbalanced nuclear equation is

^{27}\text{Al} + \rm \text{He} \longrightarrow \, ^{31}\text{P}

We can insert the subscripts, because these are the atomic numbers of the elements

_{13}^{27}\text{Al} + \, \rm _{2}\text{He} \longrightarrow \, _{15}^{31}\text{P}

That leaves only the superscript of He to be determined,

The main point to remember in balancing nuclear equations is that the sums of the superscripts must be the same on each side of the equation.  

Then

27 + x = 31, so x = 31 - 27 = 4

Then, your nuclear equation becomes

_{13}^{27}\text{Al} + \, \rm _{2}^{4}\text{He} \longrightarrow \, _{15}^{31}\text{P}

6 0
3 years ago
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