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disa [49]
3 years ago
9

How is everyone today? Just wanted to make sure everyone is alright

Mathematics
2 answers:
just olya [345]3 years ago
5 0

Answer:

not that good. struggling with depression and anxiety is hard

Step-by-step explanation:

mart [117]3 years ago
4 0

Answer:

Very good actually

Step-by-step explanation:

Because I ate CHICKEN NUGGETIES!!!!!

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A factory makes
Digiron [165]

Answer:

Each machine would produce 28,750 candies per day. hope it helps

3 0
2 years ago
T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
How can the average rate of change be identified for a function?
Digiron [165]

Answer:

Rateofchange=\frac{f(x_2)-f(x_1)}{x_2-x_1}

where x₁ and x₂ are values in the interval [x,y] respectively

Step-by-step explanation:

Well, first to determine the average rate of change of a function, you should have the interval of the values of x for the function.

So lets assume you have a function;

f(x)=x^3-4x

And the interval as [1,3]

Then the average rate of change for the function f(x) will be;

=\frac{f(x_2)-f(x_1)}{x_2-x_1}

where x₁ and x₂ are the interval coordinates x,y respectively. In this case x₁=1 and x₂=3

To find the average rate of change in this example will be;

=\frac{f(x_2)-f(x_1)}{x_2-x_1} \\\\=f(x_2)=f(3)=3^3-4(3)=27-12=15\\\\=f(x_1)=f(1)=1^3-4(1)=1-4=-3\\\\\\=x_2-x_1=3-1=2\\\\\\=\frac{15--3}{2} \\\\=\frac{18}{2} =9

8 0
3 years ago
An appliance company uses the function f
inessss [21]
Fh. = 40h + 120,  fh. = $200

200 = 40h + 120
200 - 120 = 40h
80 = 40h
 80/40  = h
  2 = h

h = 2 hours.
7 0
3 years ago
Whats 14 4/10 - 13 1/3 ASAP
monitta

Answer:

1 1/15

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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