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3 years ago

There are a few questions that I need help with.... any answers would be a great....

Mathematics

1 answer:

Gre4nikov [31]3 years ago

8 0

Answer:

1. 11 cm sq

2. $48

3. 2,697,986

4. (can't see the whole thing)

Step-by-step explanation:

1st one

I just tested out all the possibilities and that is the smallest it can get

2nd one

First, we add up 1/4 and 1/3

1/4 = 3/12

1/3 = 4/12

3/12+4/12 is 7/12 this is how much money she spent in total

5/12 is remaining which we know is $20 so if we find what 1/12 is we can multiply to find the original. 20/5=4. 1/12 = 4 now we do 4*12 which is 48 so she had $48 originally.

3rd one

This one the wording is weird, so they are just asking what minus 2 700 000 is 2014. We can just do 2,700,000-2014 which is 2,697,986

4th one

I cant see the whole problem, ill be glad to help but I can't see it rn.

*Added explanation for the 1st one*

1st one

so we know that the perimeter is 24.

What I do is just check out all the possibilities

i started off with making an even square

24/4=6

6*6=36

then I tried again

but with 1 as my width

1*2 sides=2

24-2=22

22/2=11

11*1=11 which is the smallest

It's kinda hard to explain since it really just is taking some time to find the smallest area combination.

brainliest?

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2 years ago

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3 years ago

A fraction becomes 4÷5 if 1 is added to both numerator and denominator. If, however, 5 is subtracted from both numerator and den

tia_tia [17]

Answer:

$\dfrac{7}{9}$

Step-by-step explanation:

$\dfrac{x+1}{y+1}=\dfrac{4}{5}\\\Rightarrow 5x-4y=-1$

$\dfrac{x-5}{y-5}=\dfrac{1}{2}\\\Rightarrow 2x-y=5$

Putting it in matrix form

$\begin{bmatrix}a_{1}&b_{1}\\a_{2}&b_{2}\end{bmatrix}{\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}{c_{1}}\\{c_{2}}\end{bmatrix}\\\Rightarrow\begin{bmatrix}5 & -4\\2 & -1\end{bmatrix}\begin{bmatrix}x\\ y\end{bmatrix}=\begin{bmatrix}-1\\ 5\end{bmatrix}$

From Cramer's rule we have

$x=\dfrac{\begin{vmatrix}c_1 &b_1 \\ c_2 & b_2\end{vmatrix}}{\begin{vmatrix}a_1 &b_1 \\ a_2& b_2\end{vmatrix}}\\\Rightarrow x=\dfrac{\begin{vmatrix}-1 &-4 \\ 5 & -1\end{vmatrix}}{\begin{vmatrix}5 &-4 \\ 2& -1\end{vmatrix}}\\\Rightarrow x=\dfrac{1+20}{-5+8}\\\Rightarrow x=7$

$y=\dfrac{\begin{vmatrix}a_1 &c_1 \\ a_2 & c_1\end{vmatrix}}{\begin{vmatrix}a_1 &b_1 \\ a_2& b_2\end{vmatrix}}\\\Rightarrow y=\dfrac{\begin{vmatrix}5 &-1 \\ 2 & 5\end{vmatrix}}{\begin{vmatrix}5 &-4 \\ 2& -1 \end{vmatrix}}\\\Rightarrow y=\dfrac{25+2}{-5+8}\\\Rightarrow y=9$

Verifying the results

$\dfrac{7+1}{9+1}=\dfrac{8}{10}=\dfrac{4}{5}$

$\dfrac{7-5}{9-5}=\dfrac{2}{4}=\dfrac{1}{2}$

Hence, the fraction is $\dfrac{7}{9}$ .

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3 years ago