hey guys i know this is not schol related but i just curious of how many people has a account so i can subtract it by 8
2 answers:
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1) Factor the equation first:
So either
or 
. But can never equal 0! So, we only need to solve for the second equation:
2) First, single out the term with the exponent:
Now, taking the log base 4 of each side gives us
and we can now solve for x:
So either
2) First, single out the term with the exponent:
Now, taking the log base 4 of each side gives us
and we can now solve for x:
