Answer:
I am not so sure but I think it is A.
Explanation:
If i got it wrong sorry.... :(
Answer:
d is the correct answer i think
Answer:
Partial pressure of 
in the gas was 733 torr and mass of 
in the sample was 2.12 g.
Explanation:
a) Total pressure of gas = (partial pressure of water vapour)+(partial pressure of )
Here partial pressure of water vapour is 21 torr and total pressure of gas is 754 torr.
So, partial pressure of = (total pressure of gas)-(partial pressure of water vapour) = (754 torr) - (21 torr) = 733 torr
b) Lets assume that behaves ideally. Hence-
PV=nRT
where P is pressure of , V is volume of , n is number of moles of , R is gas constant and T is temperature in kelvin
here P = 733 torr = 
= 0.9646 atm
V = 0.65 L, R = 0.082 L.atm/(mol.K), T=(273+22)K = 295 K
So, 
= 
= 0.0259 moles
As 3 moles of are produced from 2 moles of therefore 0.0259 moles of are produced from 
moles or 0.0173 moles of .
Molar mass of = 122.55 g
So mass of in sample = 
= 2.12 g
4.305 L = 4.305 × 10^6 µL
1 µL = 10^(-6) L
∴ 4.305 L × [1 µL/10^(-6) L] = 4.305 × 10^6 µL
Answer is (D) - It is exothermic and will have a negative enthalpy.
If the reactants are at a higher potential energy compared to the products, it means reactants have more energy than the products. That energy is released to the environment as heat. Due to the releasing of heat to the surrounding, the reaction is exothermic. Since the reaction is exothermic; the enthalpy of the reaction will be negative value.
