Answer:
Solute concentration will afect the rate of a chemical reaction, because you must work with molarity
Explanation:
I think that solute mass may be it can affect the rate of reaction, if you have more mass in a solute, you will also have more moles.
If you want to know more, you have to consider temperature in the reaction and the presence of catalysts. They all, affect reactions.
Answer:
0.125 moles
Explanation:
2.8 litres is equivalent to 2.8dm³
At STP,
1 mole = 22.4 dm³
x mole = 2.8 dm³
Cross multiply
22.4x = 2.8
Divide both sides by 22.4
x = 2.8/22.4
x = 0.125
Answer:
C. To determine how efficient reactions are.
D. To determine how much reactant they need.
Explanation:
When you are doing a reaction, you are hoping for a percent yield to close of 100%. You make the reaction and determine how many product you obtain. If you know the percent yield of a reaction you can calculate the amount of reactant you need to obtain a determined amount of product.
Having this in mind:
A. To balance the reaction equation. false. To calculate percent yield you need to balance the reaction before. You don't use percent yield to balance the reaction
B. To determine how much product they will need. false. You determine how much product you obtain after the reaction. How much product you need is independent of percent yield
C. To determine how efficient reactions are. true. A way to determine efficience of a reaction is with percent yield. An efficient reaction has a high percent yield.
D. To determine how much reactant they need. true. If you know percent yield of a reaction you can know how many reactant you must add to obtain the amount of product you want.
Answer:
91%
Explanation:
Since you are just trying to find the yield, take the moles of the substance from the products and divide it by the mol value of the reactants. Multiply by 100 to find percentage
0.45 ÷ 0.41 = 0.91111...
91%
Answer:
Explanation:
Given that,
Initial volume, 
The pressure changes from 73.2 kPa to 122.5 k.Pa.
We need to find the new volume occupied by the air. Let it is V₂. It can be calculated using Boyle's law such that,
So, the new volume is 
.
