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Murljashka [212]
4 years ago
5

. How many grams of NaOH would you need to make 450 mL of a 0.250 M NaOH solution

Chemistry
1 answer:
Stella [2.4K]4 years ago
7 0
You have molarity and you have volume. Use the formula :
Molarity(M)= Moles(N)/Liter(L)            to get the solution. 
450 ml= .450 L
.250 = N/.450
N=.1125 moles of NaOH.
 And since you know the moles, use the molar mass to figure out the grams.
<span> (40g/mol NaOH) x (.1125 mol) =  
4.5g of NaOH.
</span>
Hope it helps. Good luck on chemistry.
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Hydrogen gas, iodine vapor, hydrogen iodine are mixed in a flask and heated to 696°C. H2(g) + I2(g) ⇋ 2 HI(g) Kc = 52 at 696°C I
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The chemical reaction follows the equation:

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At t = 0          0.044M     0.044M              0.177M  

At t=t_{eq}    (0.044-x)M    (0.044-x)M      (0.177+x)M

The expression for K_c for the given reaction follows:

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We are given:

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Putting values in above equation, we get:

52=\frac{(0.177+x)^2}{(0.044-x)^2}

x=0.0171M

Hence, the equilibrium concentration of hydrogen gas is (0.044-x) M =(0.044-0.0171) M= 0.0269 M

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