Answer:
Option 4.) month 4
Step-by-step explanation:
we have
----> equation A
----> equation B
Solve the system by graphing
Remember that the solution is the intersection point both graphs
The solution is the point (3,27)
That means -----> For x=3 months, the populations in both functions are the same (the bacteria populations is 27)
therefore
For x> 3 months the f(x) population is greater then the g(x) population
The angles are the only constraint here that counts. If one of the three interior angles of a supposed triangle is 50 degrees and another is 80 degrees, then the third angle must be 50 degrees. Thus, we have a 50-50-80 triangle, which is isosceles though not a right triangle. If 4 feet is a measure of one of the equal sides of a supposed triangle, then obviously the adjacent side also has measure 4 ft.
The set of angles remains the same (50-50-80), but subject to the constraint mentioned above, the measure of any one of the sides has infinitely many possible values, so long as those values are positive.
Answer:
A) A dilation followed by a reflection.
Step-by-step explanation:
I went over this in class the other day. (:
Answer:
proportion of gamers who prefer console does not differ from 29%
Step-by-step explanation:
Given :
n = 341 ; x = 95 ; Phat = x / n = 95/341 = 0.279
H0 : p = 0.29
H1 : p ≠ 0.29
The test statistic :
T = (phat - p) ÷ √[(p(1 - p)) / n]
T = (0.279 - 0.29) ÷ √[(0.29(1 - 0.29)) / 341]
T = (-0.011) ÷ √[(0.29 * 0.71) / 341]
T = -0.011 ÷ 0.0245725
T = - 0.4476532
Using the Pvalue calculator from test statistic score :
df = 341 - 1 = 340
Pvalue(-0.447, 340) ; two tailed = 0.654
At α = 0.01
Pvalue > α ; We fail to reject the null and conclude that there is no significant evidence that proportion of gamers who prefer console differs from 29%
Answer:
6.7 seconds
Step-by-step explanation:
Let's calculate the maximum height covered by the object
Max height= U²Sin²tita/2g
Where g is acceleration due to gravity
Max height= 40²(sin90)²/(2*9.81)
Max height= 1600/19.62
Max height=81.55 m
Total max height= 30+81.55
Total max height= 111.55 m
Time t it will take to travel from the max height at acceleration of 4.9 m/s²
S= ut + ½at²
u= 0 at Mac height
S= 111.5 m
111.5 = ½(4.9)t²
223/4.9= t²
45.5= t²
6.745 seconds= t
6.7 seconds= t
