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matrenka [14]
3 years ago
11

If x−2/4=2, then x=10

Mathematics
2 answers:
lara31 [8.8K]3 years ago
8 0

Answer:

True.

Step-by-step explanation:

\frac{(10)-2}{4}=2\\\\\frac{8}{4}=2\\\\2=2

dem82 [27]3 years ago
6 0
If you plug 10 in for x your equation is:
(10-2)/4=2
8/4=2
2=2
So this true! X does equal 10
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Help please i dont understand
kirza4 [7]
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5 0
3 years ago
Ruden bought 6 new books for his collection, increasing his collection by 12%. How many books did he have before his purchase?
forsale [732]

Answer:

he had 44 books before he bought those 6

Step-by-step explanation:

If you multiply 6 times 2 it is 12, which means if you take away 12 from 100 that is 88. if you divided 88 by 2 (the same thing you did to the 6 to make it 12%) that would be 44.

3 0
3 years ago
PLEASE HELP !!! The height of a rectangle is twice the width and the area is 32. Find the dimensions.
Helen [10]

Answer:

The rectangle has a width of 4 and a height of 8

Step-by-step explanation:

Let the height of the rectangle be H and the width be W.

We know the height of the rectangle is twice the width, so:

H = 2W

The area of a rectangle, A, is given by A = W * H, so in this case:

32 = W * 2W

32 = 2W²

W² = 16

W = 4

Knowing that the width is 4, the height must be 8. This gives us an area of 32.

8 0
3 years ago
Read 2 more answers
Equation A: a=5b + 1
lukranit [14]

ANSWER:

a = 11

b = 2

Explaination:

We have two equations:

a = 5b + 1 .....................(1)

a = 3b + 5.....................(2)

Here we use substitution method in order to solve the set of equations.

put a=3b+1 to equation (1)

3b + 5 = 5b + 1

Solve for b

5 = 5b -3b + 1

5-1 =2b

4 = 2b

b = 2

Now put the value of b = 2 into the equation (1) or (2)

a = 5b + 1

a = 5(2) + 1

a = 10 + 1

a = 11

5 0
3 years ago
Solve for x in the equation x squared + 11 x + StartFraction 121 Over 4 EndFraction = StartFraction 125 Over 4 EndFraction.
Ira Lisetskai [31]

Answer:

Below

Step-by-step explanation:

● x^2 + 11x + 121/4 = 125/4

Substract 125/4 from both sides:

● x^2 + 11x + 121/4-125/4= 125/4 -125/4

● x^2 + 11x - (-4/4) = 0

● x^2 +11x -(-1) = 0

● x^2 + 11 x + 1 = 0

This is a quadratic equation so we will use the determinanant (b^2-4ac)

● a = 1

● b = 11

● c = 1

● b^2-4ac = 11^2-4*1*1 = 117

So this equation has two solutions:

● x = (-b -/+ √(b^2-4ac) ) / 2a

● x = (-11 -/+ √(117) ) / 2

● x = (-11 -/+ 3√(13))/ 2

● x = -0.91 or x = -10.9

Round to the nearest unit

● x = -1 or x = -11

The solutions are { -1,-11}

6 0
3 years ago
Read 2 more answers
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