Hello,
Let's r the ration
We suppose x ≠0
x=r*(x-2)==>r=x/(x-2)
x+3=r*x==> (x+3)/x=x/(x-2)==>(x+3)(x-2)=x²
==>x²+3x-2x-6=x² ==>x-6=0==>x=6
x-2=6-4=4
x=6
x+3=6+3=9
6=4*3/2
9=6*3/2
Ration 3/2
First term: 4
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Answer:1 1/6
Step-by-step explanation:
Answer:
Step-by-step explanation:
When the coefficients don't lend themselves to solution by substitution or elimination, then Cramer's Rule can be useful. It tells you the solutions to
are ...
- ∆ = bd -ea
- x = (bf -ec)/∆
- y = (cd -fa)/∆
Using that rule here, we find ...
∆ = 5·3 -6·2 = 3
a = (5·54 -6·41)/3 = 5·18 -2·41 = 90 -82 = 8
s = (41·3 -54·2)/3 = 41 -18·2 = 5
This math can be performed in your head, which is the intent of formulating the rule in this way.
_____
Similarly, if you expect the solutions to be small integers (as here), then graphing is another viable solution method.
_____
<em>Comment on the question</em>
We're sad to see than only 16 tickets were sold to the two performances by the symphonic band.
Answer:
The number of hot beverages sold were 45 and the number of cold beverages sold were 180.
Step-by-step explanation:
Let the number of cold beverages sold be 
And the number of hot beverages sold be 
According to the question:
c=4
h...
1.5
c + 2
h = Sale of any day
Part1:
For Saturday.
The sale is of
360
then
1.5
c +
2
h =
360
Part 2:
Following the method of substitution.
And plugging the values of c=4
h...in equation where the sales of Saturday is given.
1.5
c + 2
h =360
1.5
4
h + 2
h =360
6
h + 2
h= 360
8
h=360
Dividing both sides with 8.
h=
h=45
Inserting h=45 in c=4
h...
we have c=4
45 = 180
So the number of hot beverages sold were 45 and the number of cold beverages sold were 180.