In what interval is the function f(x)=squareroot x^2+5x+4 defined
2 answers:
9514 1404 393
Answer:
(-∞, -4] U [-1, ∞)
Step-by-step explanation:
The quadratic expression factors as ...
x^2 +5x +4 = (x +4)(x +1)
The zeros of this expression are where these factors are zero, at x=-4 and x=-1. The product is negative when one factor is negative and the other is positive, in the region -4 < x < -1. It is non-negative elsewhere. f(x) is defined where the quadratic is not negative, on the union of intervals ...
(-∞, -4] U [-1, ∞)
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Answer:
Step-by-step explanation:
y = 6x − 4
y = 5x − 3
A: chose a value for x(input) and get the out put (y) because the equation already in the slope intercept mode:y=mx+b
x y=6x-4 y=5x-3
1 y=2 y=2
2 y=8 y=7
0 -4 -3
slope :
y=6x-4 slope is 6 y intercept(0,-4)
y=5x-3 slope is 5 y intercept (0,-3)
solution of the pair of equation is the point of intersection :
6x-4=5x-3
6x-5x=-3+4
x=1 and y=6x-4 ⇒ y=6-4=2
<h2>(1,2)</h2>
In a basket, 5/9 of the fruits are apples and the rest are oranges. 3/10 of the apples are green in colour. There are 15 green apples. How many fruits are there in the basket?
