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DiKsa [7]
3 years ago
5

Which statement describes the distribution of charge in an atom?

Physics
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

hope this helps

Explanation:

one in which a positively charged nucleus is surrounded by one or more negatively charged electrons.

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A 1-meter-long wire consists of an inner copper core with a radius of 1.0 mm and an outer aluminum sheathe, which is 1.0 mm thic
Mazyrski [523]

Answer:

The total resistance of the wire is = 1.917\times10^{-3}

Explanation:

Since the wires will both be in contact with the voltage source at the same time and the current flows along in their length-wise direction, the two wires will be considered to be in parallel.

Hence, for resistances in parallel, the total resistance, R_{Total}

\frac{1}{R_{Total}}  =\frac{1}{R_{cu}  }+\frac{1}{R_{al}}

Parameters given:

Length of wire = 1 m

Cross sectional area of copper A_{cu}= \pi r^{2}= \pi \times (1\times 10^{-3}  )^{2} =3.142\times10^{-6} m^{2}

Cross sectional area of aluminium wire  

A_{al}= \pi( R^{2}-r^{2})\\\\ = \pi \times [ (2\times 10^{-3}  )^{2}-(1\times 10^{-3}  )^{2}] =9.42\times10^{-6} m^{2}\\

Resistivity of copper \rho _{cu}=1.7\times 10^{-8}  \Omega .m

Resistivity of Aluminium \rho _{al}=2.8\times 10^{-8}  \Omega .m

Resistance of copper R_{cu}= \frac{\rho_{cu} \times l}{A_{cu} }  =\frac{1.7\times 10^{-8} \times 1}{3.142\times10^{-6} } =5.41\times 10^{-3}\Omega

Resistance of aluminium R_{al}= \frac{\rho_{al} \times l}{A_{al} }  =\frac{2.8\times 10^{-8} \times 1}{9.42\times10^{-6} } =2.97\times 10^{-3}\Omega

The total resistance of the wire can be obtained as follows;

\frac{1}{R_{Total}}  =\frac{1}{5.41\times10^{-3}  }+\frac{1}{2.97\times10^{-3}}=521.52\frac{1}{\Omega}

R_{Total}= 1.917\times 10^{-3}\Omega

∴ The total resistance of the wire = 1.917\times 10^{-3}\Omega

4 0
3 years ago
Read 2 more answers
Examine the scenario.
frutty [35]
I Think The answer is d I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
6 0
3 years ago
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Iron filings were sprinkled around these two magnets. What do the iron filings
Sever21 [200]

Answer:

B. They show the pattern made by the magnetic field lines around the

magnets

Explanation:

Using iron fillings, the pattern of the magnetic field lines around a bar magnet can be known.

Magnetic field lines are the line of force around a bar magnet.

  • These iron fillings will trace the pattern of the magnetic field around the magnet.
  • The domains of the iron fillings begins to align and orient with that of the prevailing magnetic field around.
  • Those areas with the strongest force will attract more fillings and those far away will attract lesser fillings.
3 0
3 years ago
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A car travels north for 20 km. The car then travels south for 35 km.
PSYCHO15rus [73]

Answer: -15 km

Explanation:

8 0
3 years ago
Two plastic bowling balls, 1 and 2, are rubbed with cloth until they each carry a uniformly distributed charge of magnitude 0.50
galben [10]

Answer:

The right solution is "4.5\times 10^{-10} \ Cm".

Explanation:

Given that,

q = 0.50 nC

d = 900 mm

As we know,

⇒ P=qd

By putting the values, we get

⇒     =0.50\times 900

⇒     =(0.50\times 10^{-9})\times 0.9

⇒     =4.5\times 10^{-10} \ Cm  

5 0
3 years ago
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