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Sliva [168]
3 years ago
15

A movie stunt double is supposed to run across the top of a train (in the opposite direction that the train is moving) and just

barely jump off before reaching a tunnel, but after reaching the end of the train (starting from the front). If the train is moving at 150 km/hr, is 2 km long and the tunnel is 20 km away from the end (where the stunt double is going to jump from), how fast (in km/hr) will the stunt double need to run
Physics
1 answer:
Semmy [17]3 years ago
3 0

Answer:

the required speed/velocity of the stunt double is 13.633 km/h

Explanation:

Given the data in the question;

velocity of train V = 150 km/h

distance = length of train + distance between the tunnel and the end

= 2 km + 20 km = 22 km

first we calculate time t taken by the train to reach the tunnel;

t = distance / velocity

we substitute

t = 22 km / 250 km/h

t = 0.1467 hr

so the velocity of the of the stunt double will be;

velocity = distance / time

we substitute

velocity = 2 km / 0.1467 hr

velocity = 13.633 km/h

Therefore, the required speed/velocity of the stunt double is 13.633 km/h

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3 years ago
A lump of clay whose rest mass is 4 kg is travelling at three-fifths the speed of light when it collides head-on with an identic
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Answer:

mass of the composite lump is 10 kg

Explanation:

given data

mass = 4 kg

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mass of composite lump

solution

we know energy is conserved so

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and

E(1) release+ E(2) release = E(1,2) rest

so γ(1)m(1)c² + γ(2)m(2)c²  = Mc²    ..........................1

that why here

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and

γ = 1 / √(1 − v²/c²)           .......................3

put here v = 3 and c is 5

γ = 1 /√(1 − 9/25)

γ =  5/4

so

γ(1) = γ(2) = γ = 5/4  

so from equation 1

γ(1)m(1)c² + γ(2)m(2)c²  = Mc²

M = 2γm0

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A
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Answer:

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