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3 years ago

5

35 344 minus 17 943 is 17 401 but to show the sum in how to get 17 401 is hard. In calculating I keep getting 22 601. please hel

p me show how to get 17 401

1 answer:

bezimeni [28]3 years ago

8 0

Well umm check calculator again maybe you did a mistake in typing one of the numbers

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Write two division expressions that have the same value as 36.8 divided by 2.3 (16)

yarga [219]

64 divided by 4=16

144 divided by 9=16

7 0

3 years ago

What number is exactly half way between 1/9 and 1/3

nata0808 [166]

Answer:

1/5

Step-by-step explanation:

1/9=0.11

1/3=0.33

1/5=0.20

I don't really know the answer but I tried.

6 0

3 years ago

Hey:)can you please help me posted picture of question

AysviL [449]

The correct option is (A) x^6 + x^5 - 2x^4 - 2x^3 + 3x^2 + 6x - 9

Explanation:
The product of two polynomials:
(x^3 + x^2 -3)(x^3 - 2x + 3)

Row1: x^6 x^5 -3x^3
Row2: -2x^4 -2x^3 6x
Row3: 3x^3 3x^2 -9

Add all of the above rows:
x^6 + x^5 - 3x^3 -2x^4 - 2x^3 + 6x + 3x^3 + 3x^2 -9

x^6 + x^5 - 2x^4 - 2x^3 + 3x^2 + 6x - 9 (Option A)

3 0

3 years ago

On a map the perimeter of the is 0.251 meters. The actual perimeters of the park is 1,000 times as large. What is the actual per

raketka [301]

The actual perimeter of the park is $\boxed{\bf251{\text{ meters}}}$ .

Further explanation:

Given:

The perimeter of the park is on a map $0.251{\text{ meters}}$ . The measured perimeter of the park is 1000 times as large.

Calculation:

The distance of the closed figure is called as the perimeter.

The perimeter of the attached Figure 1 can be calculated as,

$\begin{aligned}{\text{Perimeter}}&=a+a+b+b\\&=2\left({a+b}\right)\\\end{aligned}$

Here, $x,y{\text{ and }}z$ is the length of the shape.

From place value chart, 10 tens is equal to 1 hundreds.

Tenths are one place after the decimal and hundredths are two places after the decimal.

Two tenths can be written in the form of decimal as follows:

$\dfrac{2}{{10}}=0.2$

Five hundredths can be written in the form of decimal as follows:

$\dfrac{5}{{100}}=0.05$

One thousandths can be written in the form of decimal as follows:

$\dfrac{1}{{1000}}=0.001$

Therefore, the number 0.251 can be written as,

$\begin{aligned}0.251&=\frac{2}{{10}}+\frac{5}{{100}}+\frac{1}{{1000}}\\&=0.2+0.05+0.001\\&=0.251\\\end{aligned}$

On the map the perimeter of the park is $0.251{\text{ meters}}$ .

Let ${\text{P}}$ be the actual perimeter of the park.

The actual perimeter of the park can be calculated as follows,

$\begin{aligned}{\text{P}}&=0.251\times1000\\&=251{\text{ meters}}\\\end{aligned}$

Thus, the actual perimeter of the park is $\boxed{\bf251{\text{ meters}}}$ .

Learn more:

1. Learn more about problem on function brainly.com/question/1632445

2. Learn more about problem on triangle brainly.com/question/7437053

3. Learn more about problem on range and domain of functions brainly.com/question/3412497

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Numbers

Keywords: Perimeter, park, map, , measured, 1000 times large, distance, closed figure, length, shape, place value chart, hundreds, tenths.

6 0

3 years ago

Read 2 more answers

Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$

$\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }$

$\mathbf{ YX = \sqrt{(3)^2+(6)^2} }$

$\mathbf{ YX = \sqrt{9+36} }$

$\mathbf{ YX = \sqrt{45} }$

$\mathbf{ YX = \sqrt{9*5} }$

$\mathbf{ YX = 3 \sqrt{5} }$

Thus; the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

8 0

3 years ago