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Harrizon [31]
3 years ago
7

What is the maximum mass of aluminum chloride that can be formed when reacting 18.0 g of aluminum with 23.0 g of chlorine?

Chemistry
2 answers:
kumpel [21]3 years ago
5 0

Answer : The maximum mass of aluminium chloride formed can be 28.8 grams.

Solution : Given,

Mass of Al = 18.0 g

Mass of Cl_2 = 23.0 g

Molar mass of Al = 27 g/mole

Molar mass of Cl_2 = 71 g/mole

Molar mass of AlCl_3 = 133.5 g/mole

First we have to calculate the moles of Al and Cl_2.

\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{18.0g}{27g/mole}=0.667moles

\text{ Moles of }Cl_2=\frac{\text{ Mass of }Cl_2}{\text{ Molar mass of }Cl_2}=\frac{23.0g}{71g/mole}=0.324moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2Al+3Cl_2\rightarrow 2AlCl_3

From the balanced reaction we conclude that

As, 3 mole of Cl_2 react with 2 mole of Al

So, 0.324 moles of Cl_2 react with \frac{0.324}{3}\times 2=0.216 moles of Al

From this we conclude that, Al is an excess reagent because the given moles are greater than the required moles and Cl_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of AlCl_3

From the reaction, we conclude that

As, 3 mole of Cl_2 react to give 2 mole of AlCl_3

So, 0.324 moles of Cl_2 react to give \frac{0.324}{3}\times 2=0.216 moles of AlCl_3

Now we have to calculate the mass of AlCl_3

\text{ Mass of }AlCl_3=\text{ Moles of }AlCl_3\times \text{ Molar mass of }AlCl_3

\text{ Mass of }AlCl_3=(0.216moles)\times (133.5g/mole)=28.8g

Therefore, the maximum mass of aluminium chloride formed can be 28.8 grams.

Agata [3.3K]3 years ago
4 0

<span>Number of moles of aluminum chloride = 0.216. </span>
<span>Mass of compound = Number of moles x Molar Mass </span>
<span>= 0.216mol x [ 37 + 3(35.5) ]g/mol </span>
<span>= 30.996 </span>
<span>= 31.0g (3 s.f.)</span>
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