ML to L is a factor of 1000. Just multiply your initial number by 1000.
Answer:
6 mol
Explanation:
Discussion
The answer is very nearly six. I will use rounded whole numbers to get the molar mass. Every periodic table is different so you will have to redo my numbers using your periodic table.
The trick is to find 1 mole of CH4 and divide that into 96.
Givens
96.0 grams of CH4
Solution
Find 1 mol of CH4
1 * 1C = 1 * 12 = 12 grams of Carbon in 1 mol of CH4
4 * H = 4 * 1 = 4 grams of Hydrogen in 1 mol of CH4
Total = 16 grams of C and H in 1 mol of CH4
Find 96 grams in mols.
Formula
mol = given mass / molar mass
given mass = 96 grams
molar mass = 16 grams
Mol = 96 / 16
Answer: mol = 6
Answer:
43.13Kg of melamine
Explanation:
The problem gives you the mass of urea and two balanced equations:
First we need to calculate the number of moles of urea that are used in the reaction, so:
molar mass of urea =
The problem says that you have 161.2Kg of urea, so you take that mass of urea and find the moles of urea:
161.2Kg of urea2684 moles of urea
Now from the stoichiometry you have:
2684 moles of urea = 447 moles of melamine
The molar mass of the melamine is so we have:
= 5637.64 g of melamine
Converting that mass of melamine to Kg:
5637.64 g of melamine * = 56.38 Kg of melamine, that is the theoretical yield of melamine.
Finally we need to calculate the mass of melamine with a yield of 76.5%, so we have:
%yield = 100*(Actual yield of melamine / Theoretical yield of melamine)
Actual yield of melamine = = 43.13Kg of melamine
<u>Answer:</u> The amount of calcium hydroxide needed to react is 2.04 moles
<u>Explanation:</u>
We are given:
Moles of phosphoric acid = 1.36 moles
For the given chemical equation:
By Stoichiometry of the reaction:
2 moles of phosphoric acid reacts with 3 moles of calcium hydroxide
So, 1.36 moles of phosphoric acid will react with = of calcium hydroxide
Hence, the amount of calcium hydroxide needed to react is 2.04 moles