Answer: The pH of a 4.4 M solution of boric acid is 4.3
Explanation:
at t=0 cM 0 0
at eqm 
So dissociation constant will be:
Give c= 4.4 M and 
= ?
Putting in the values we get:
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)
![[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D4.4%5Ctimes%200.000011%3D4.8%5Ctimes%2010%5E%7B-5%7DM)
Also ![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
![pH=-log[4.8\times 10^{-5}]=4.3](https://tex.z-dn.net/?f=pH%3D-log%5B4.8%5Ctimes%2010%5E%7B-5%7D%5D%3D4.3)
Thus pH of a 4.4 M 
solution is 4.3
Atoms are made up of three subatomic particles called protons, neutrons, and electrons.
Protons and neutrons are located in the nucleus.
All protons have a positive charge.
All neutrons have no charge or are neutral.
Electrons orbit around the nucleus and have a negative charge.
To calculate the average mass of the element, we take the summation of the product of the isotope and the percent abundance. We calculate as follows:
Average atomic mass = .374 ( 184.953 amu ) + .626 ( <span>186.958 amu ) = 186.208 amu
Hope this answers the question. Have a nice day.</span>
The temperature will be 1200K if the volume remained constant
calculation
This is calculated using gay lussac law formula, that is P1/ T1=P2/T2 since the volume is constant
P1 = 100 Kpa
T1= 300 K
P2= 400 Kpa
T2=?
by making T2 the subject of the formula T2 =( P2 xT1)/P1
T2 is therefore = (400 KPa x 300 K) / 100 Kpa = 1200 K
16: solar energy, 17: glucose, 18: heat, 19: atp
